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∙ 11y agoFirst, let us find the height of one side of the cube, we have;
S= cube root of 64
S= 4.
Since the diameter is 4 cm, the radius will be 2 cm.
now, solve it by using the formula:
V= PI.r squared . h
V= 3.14. 2 cm squared. 4 cm
V= 3.14. 16
v=50.24 cubic centimeter
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∙ 11y ago(4/27)*pi*R3*tan(x) R being the radius of the base of the cone.
Millimeter centimeter meter kilometer is the right order
It is 2*r^2.
kilometer
The answer depends on the cylinder.
volume of a regular right circular cylinder is V=pi(r2)h since the radius is (a) then the height of the circular cylinder would be (2a) so the volume of the largest possible right circular cylinder is... V=2(pi)(r2)(a) with (pi) being 3.14159 with (r) being the radius of the circle on the top and bottom of the cylinder with (a) being the radius of the sphere
(4/27)*pi*R3*tan(x) R being the radius of the base of the cone.
Find the dimensions of the rectangle of largest area that can be inscribed in a circle of radius a in C programming
Millimeter, centimeter, meter, kilometer.
Millimeter centimeter meter kilometer is the right order
Let the radius of the largest sphere that can be carved out of the cube be r cm.The largest sphere which can be carved out of a cube touches all the faces of the cube.∴ Diameter of the largest sphere = Edge of the cube⇒ 2r = 7 cm∴ Volume of the largest sphere
It is 2*r^2.
kilometer
kilometer
up to a 30 centimeter(12)in.
The answer depends on the cylinder.
The largest rectangle would be a square. If the circle has radius a, the diameter is 2a. This diameter would also be the diameter of a square of side length b. Using the Pythagorean theorem, b2 + b2 = (2a)2. 2b2 = 4a2 b2 = 2a2 b = √(2a2) or a√2 = the length of the sides of the square The area of a square of side length b is therefore (√(2a2))2 = 2a2 which is the largest area for a rectangle inscribed in a circle of radius a.