This exercise could have been a piece o' cake, and fun in its own right,if you had just told us what the "factor of ..." number is.By whatever factor the radius increases, the volume increases by the cubeof that number.
Surface area to volume ratio in nanoparticles have a significant effect on the nanoparticles properties. Firstly, nanoparticles have a relative larger surface area when compared to the same volume of the material. For example, let us consider a sphere of radius r: The surface area of the sphere will be 4πr2 The volume of the sphere = 4/3(πr3) Therefore the surface area to the volume ratio will be 4πr2/{4/3(πr3)} = 3/r It means that the surface area to volume ration increases with the decrease in radius of the sphere and vice versa.
The volume is 94 US gallons.
A sphere cannot have a 17 inch height, if it has a 6 inch radius. If it has a 6 inch radius, the height (diameter, in this case), would be 2 times the radius, which is 12. If it was a sphere with 6 inch radius (and not using height), then you use the formula, 4/3(pi)r^3. = 4/3 * pi * 6^3 = 288 pi ≈ 904.779 inches cubed. Dingbot is: 1. over-sensitive to long answers, 2. correct to ping over-exact answers pasted from [Windows] Calculator. Folks, 4 to 6 significant figures are enough for us engineers and mechanics - any more is just bragging.
A cylinder with a radius of 21 inches and a height of 98 inches has a volume of 135,773.35 cubic inches. This cylinder would have a volume of 587.763 US gallons.
Given only one radius measure, the most likely shape is a sphere. A sphere with a 1 foot radius has a volume of 26.1 Imperial gallons (31.3 US gal). Given only one radius measure, the most likely shape is a sphere. A sphere with a 1 foot radius has a volume of 26.1 Imperial gallons (31.3 US gal). Given only one radius measure, the most likely shape is a sphere. A sphere with a 1 foot radius has a volume of 26.1 Imperial gallons (31.3 US gal). Given only one radius measure, the most likely shape is a sphere. A sphere with a 1 foot radius has a volume of 26.1 Imperial gallons (31.3 US gal).
The formula to find the volume of a sphere us V = 4/3πr3, where V is volume, π is pi, which can be rounded to 3.14, and r is the radius. In order to find the volume of your sphere, the radius has to have a length unit, such as 10.2 cm or 10.2 inches.
This exercise could have been a piece o' cake, and fun in its own right,if you had just told us what the "factor of ..." number is.By whatever factor the radius increases, the volume increases by the cubeof that number.
Surface area to volume ratio in nanoparticles have a significant effect on the nanoparticles properties. Firstly, nanoparticles have a relative larger surface area when compared to the same volume of the material. For example, let us consider a sphere of radius r: The surface area of the sphere will be 4πr2 The volume of the sphere = 4/3(πr3) Therefore the surface area to the volume ratio will be 4πr2/{4/3(πr3)} = 3/r It means that the surface area to volume ration increases with the decrease in radius of the sphere and vice versa.
Well, darling, the volume of a sphere is calculated using the formula V = (4/3)πr^3. So, plug in the radius of 12 cm, and you'll find that the volume is approximately 7238.23 cubic centimeters. So, there you have it, sweetie, now go impress someone with your newfound knowledge.
A cylinder that has a radius of 5' and height of 25' has a volume of 14,688 US gallons.
The volume is 8,460.27 US gallons.
The volume is 94 US gallons.
The volume of a cylinder with a radius of 108 inches and a height of 206 inches is 32,677.8 US gallons.
A sphere cannot have a 17 inch height, if it has a 6 inch radius. If it has a 6 inch radius, the height (diameter, in this case), would be 2 times the radius, which is 12. If it was a sphere with 6 inch radius (and not using height), then you use the formula, 4/3(pi)r^3. = 4/3 * pi * 6^3 = 288 pi ≈ 904.779 inches cubed. Dingbot is: 1. over-sensitive to long answers, 2. correct to ping over-exact answers pasted from [Windows] Calculator. Folks, 4 to 6 significant figures are enough for us engineers and mechanics - any more is just bragging.
A cylinder with a radius of 21 inches and a height of 98 inches has a volume of 135,773.35 cubic inches. This cylinder would have a volume of 587.763 US gallons.
The volume of a cube is L3. The volume of a sphere is 4/3 π r3 . If L=2r, Vcube=8r3. Comparing the volume of the cube with a side 2r and a sphere with a diameter of 2r where the r's are equal gives us: Vcube/Vsphere= (8r3)/(4/3 π r3 ) or (8x3)/(πx4) As π roughly equals 3 the equation simplifies to: Vcube/Vsphere=2 or a cube with its side equal to the diameter of a sphere has a volume approximately twice that of the sphere.