What is the wavelength of 6.0 x10 -14?

Answer 1

The wavelength of a photon can be calculated using the formula ( \lambda = \frac{h \cdot c}{E} ), where ( h ) is Planck's constant ((6.626 \times 10^{-34} , \text{Js})), ( c ) is the speed of light ((3.00 \times 10^8 , \text{m/s})), and ( E ) is the energy in joules. If ( 6.0 \times 10^{-14} , \text{J} ) is the energy, the wavelength ( \lambda ) would be approximately ( 3.31 \times 10^{-12} , \text{m} ) or 3.31 picometers. This wavelength corresponds to high-energy photons, such as X-rays or gamma rays.