In order to find the weighted mean of this set of the data, we need to know the weight for each data in the set, and this information is not given in your question.
Definition: When each number ai is to have weight wi, the weighted mean is equal to
(w1a1+w2a2 + ... + wnan)/(w1 + w2 + ... + wn).
If you mean: 8 9 10 11 and 12 then the average mean is 10
The mean is 8 because: (1+6+10+11+12)/5=8 We know that the Arithmetic Mean of a data set = (sum of all the items)/ number of items. =(1+6+10+11+12)/5 =(40)/5 =8. The Arithmetic Mean of 1, 6, 10, 11, and 12 is 8.
To find the mean you would add up all the numbers 7+9+10+11+11+12 and get 60. Then divide by how many numbers you added by, in this case 6. So 60 ÷ 6 = 10. The mean would be: 10
Mean = 14 Median = 12 Mode = 12
Yes. In the set (9, 10, 11, 12, 13) 11 is the median and the mean.
If you mean: 8 9 10 11 and 12 then the average mean is 10
The mean is 8 because: (1+6+10+11+12)/5=8 We know that the Arithmetic Mean of a data set = (sum of all the items)/ number of items. =(1+6+10+11+12)/5 =(40)/5 =8. The Arithmetic Mean of 1, 6, 10, 11, and 12 is 8.
Mean: 20.2222222 Median: 12 Mode: 11 Range: 79
well at 11 she weighed 90 pound and at 13 she weighed 105
To find the mean you would add up all the numbers 7+9+10+11+11+12 and get 60. Then divide by how many numbers you added by, in this case 6. So 60 ÷ 6 = 10. The mean would be: 10
It is (8+6+11+12+13)/5 = 10
-9,-11,-8,-12,-10
That's a bit heavy, but I suppose there are several people who weighed that much at birth.
Mean = 14 Median = 12 Mode = 12
mean = 19 median = 12 mode = 12
Yes. In the set (9, 10, 11, 12, 13) 11 is the median and the mean.
7, 10, 11, 12, 13, 14, 17