Mass.
6.3 X 10^21 atoms phosphorous (1 mole P/6.022 X 10^23)(30.97 grams/1 mole P)
= 0.32 grams of phosphorous
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Oh honey, let me break it down for you. Avogadro's number tells us that 1 mole is equal to 6.022 x 10^23 atoms. So, to find out how many moles are in 1.25 x 10^25 atoms of phosphorus, you just need to divide the number of atoms by Avogadro's number. That gives you approximately 20.75 moles of phosphorus.
The numbers 10-15-10 on a fertilizer indicate its N-P-K ratio, representing the percentage of nitrogen (N), phosphorus (P), and potassium (K) in the mix. Specifically, this means the fertilizer contains 10% nitrogen, 15% phosphorus, and 10% potassium. Nitrogen promotes leafy growth, phosphorus supports root development and flowering, and potassium enhances overall plant health and resilience. This specific ratio is often used for plants that require more phosphorus for blooming or fruiting.
The atomic weight of copper is 63.546 grams per mole. 129 kg is equal to 129000 grams. So there are 2030.03 moles of copper. There are 6.022 x 10^23 copper atoms in a mole. So there are 12.22 x 10^26 atoms.
The numbers 10-15-10 on a fertilizer bag represent the percentages of the three primary nutrients it contains: nitrogen (N), phosphorus (P), and potassium (K), respectively. In this case, the fertilizer contains 10% nitrogen, 15% phosphorus, and 10% potassium. Nitrogen promotes leafy growth, phosphorus supports root development and flowering, and potassium enhances overall plant vigor and disease resistance. This balanced formulation is often used for a variety of plants to ensure healthy growth.
To convert a CGPA from a 10-point system to a 4-point system, you can use the formula: ( \text{CGPA (4-point)} = \left( \text{CGPA (10-point)} \times 4 \right) / 10 ). For example, if your CGPA is 8.0 in a 10-point system, it would convert to a 3.2 in the 4-point system. This method maintains the proportionality between the two scales.
1 gram phosphorus (1mol P/30.97 grams)(6.022 X 10^23/1mol P) = 1.9 X 10^22 atoms of phosphorus
There are 2.21 x 10^24 atoms of phosphorus in 3.65 moles of phosphorus triiodide.
The prefix deca- means 10, so there are 10 oxygen atoms in a molecules of tetraphosphorus decoxide. The formula is P4O10
The ratio of phosphorus atoms to oxygen atoms in a compound can vary depending on the specific compound. For example, in phosphorus pentoxide (P4O10), the ratio is 4:10.
The formula for Phosphorus(V) Oxide [which has 10 oxygen atoms in a molecule] is P4O10.
There are 6.022 x 10^23 atoms in one mole of phosphorus.
There are 1 mol of phosphorus atoms in 1 mol of copper (II) phosphate. Therefore, in 3.30 mol of copper (II) phosphate, there are 3.30 mol of phosphorus atoms, which is equivalent to 3.30 x 6.022 x 10^23 = 1.97 x 10^24 atoms of phosphorus.
The mass of 4.21 x 10^23 atoms of phosphorus (P) can be calculated by multiplying the number of atoms by the atomic mass of phosphorus. The atomic mass of phosphorus is approximately 31. Therefore, the mass of 4.21 x 10^23 atoms of phosphorus would be around 1.30 x 10^25 grams.
Simple. 3 * 6.022 X 10^23 = 1.81 X 10^24 atoms of P
To convert atoms to moles, you divide by Avogadro's number, which is approximately 6.022 x 10^23. Therefore, 1.20x10^25 atoms of phosphorus is equal to 20 moles of phosphorus.
To determine the number of phosphorus atoms in 30.973 grams, you would first convert the mass to moles using the molar mass of phosphorus (30.973 g/mol). Then, you would use Avogadro's number (6.022 x 10^23 atoms/mol) to find the number of phosphorus atoms, which would be 30.973 grams / 30.973 g/mol * 6.022 x 10^23 atoms/mol.
The formula for Phosphorus(V) Oxide [which has 10 oxygen atoms in a molecule] is P4O10.