Mass.
6.3 X 10^21 atoms phosphorous (1 mole P/6.022 X 10^23)(30.97 grams/1 mole P)
= 0.32 grams of phosphorous
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The atomic weight of copper is 63.546 grams per mole. 129 kg is equal to 129000 grams. So there are 2030.03 moles of copper. There are 6.022 x 10^23 copper atoms in a mole. So there are 12.22 x 10^26 atoms.
10
10 t(US) = 20000 lb
If you mean point of (1, 4) and slope of -10 then y = -10x+14
Weight = (Mass)(Acceleration due to gravity)w=(m)(a)(*note don't really think so but don't wanna delete answers I am not that old.)weight = mass (kilograms) x gravity (10 Nkg-1)The formula weight is the same thing as the molecular weight. For example,NO2 : (Look up masses on the periodic table, multiply by how much atoms there are, and add the products) N-14.01 g x 1= 14.01 gO2- 16 x 2=+ 32.00 g_______46.01g (This is your molecular weightwhich is the same as your formula weight)
There are approximately 6.022 x 10^22 phosphorus atoms in 1.0 gram of phosphorus, based on Avogadro's number.
There are 2.21 x 10^24 atoms of phosphorus in 3.65 moles of phosphorus triiodide.
There are 10 oxygen atoms in one molecule of tetra-phosphorus decaoxide. Each phosphorus atom is bonded to 5 oxygen atoms, giving a total of 4 phosphorus atoms and 10 oxygen atoms in the molecule.
The ratio of phosphorus atoms to oxygen atoms in a compound can vary depending on the specific compound. For example, in phosphorus pentoxide (P4O10), the ratio is 4:10.
The formula for Phosphorus(V) Oxide [which has 10 oxygen atoms in a molecule] is P4O10.
There are 1 mol of phosphorus atoms in 1 mol of copper (II) phosphate. Therefore, in 3.30 mol of copper (II) phosphate, there are 3.30 mol of phosphorus atoms, which is equivalent to 3.30 x 6.022 x 10^23 = 1.97 x 10^24 atoms of phosphorus.
There are 6.022 x 10^23 atoms in one mole of phosphorus.
The mass of 4.21 x 10^23 atoms of phosphorus (P) can be calculated by multiplying the number of atoms by the atomic mass of phosphorus. The atomic mass of phosphorus is approximately 31. Therefore, the mass of 4.21 x 10^23 atoms of phosphorus would be around 1.30 x 10^25 grams.
There are approximately 1.81 x 10^24 atoms in 3 moles of phosphorus. This is calculated by multiplying Avogadro's number (6.022 x 10^23) by the number of moles of phosphorus (3).
To convert atoms to moles, you divide by Avogadro's number, which is approximately 6.022 x 10^23. Therefore, 1.20x10^25 atoms of phosphorus is equal to 20 moles of phosphorus.
To determine the number of phosphorus atoms in 30.973 grams, you would first convert the mass to moles using the molar mass of phosphorus (30.973 g/mol). Then, you would use Avogadro's number (6.022 x 10^23 atoms/mol) to find the number of phosphorus atoms, which would be 30.973 grams / 30.973 g/mol * 6.022 x 10^23 atoms/mol.
There are 4.54 x 10^24 atoms in 7.52 moles of Phosphorus because 1 mole of Phosphorus contains 6.022 x 10^23 atoms. Multiplying this by the number of moles gives the total number of atoms in 7.52 moles.