There is no specific answer to this question. Assuming width is the smaller of the two dimensions, then the width, W, can be any number that satisfies
0 < W <= sqrt(20) cm. There are an infinite number of values for W.
The other side of the rectangle will be 20/W cm.
Multiply the length of the rectangle by the width. For example: 34cm x 20cm = 680cm2
Area of a rectangle = length * width = 72 feet-squared
multiply the width by the length, e.g. 5cm= width, 4cm= length, 5x4= 20, 20cm squared
Width of rectangle: 180/15 = 12 cm
11.5 cm
20cm squared
Multiply the length of the rectangle by the width. For example: 34cm x 20cm = 680cm2
Area of a rectangle = length * width = 72 feet-squared
multiply the width by the length, e.g. 5cm= width, 4cm= length, 5x4= 20, 20cm squared
Width of rectangle: 180/15 = 12 cm
trick question
Simply add the numbers up For example, If the area of a semicirce is 20cm squared and the area of a rectange is 25cm squared, then the total area would be 20 + 25 = 45
11.5 cm
4.5 inches.
17.6 squared inches
Width = 161/14 = 11.5 cm
width = 375/25 = 15 inches