y=4x-12-3 is the equation of a straight line. It does not have a vertex.
Did you mean y=x squared - 12x - 3 ?
The vertex of the positive parabola turns at point (-2, -11)
Need signs between terms.
It is: y = -4x+12
8x + 12 = 4x - 4 8x - 4x = -4 - 12 4x = -16 x = -4
4x-5=7 4x=12 x=3
The vertex of the positive parabola turns at point (-2, -11)
Need signs between terms.
If: 4x-4 = 12 Then: x = 4
If: 4x+(-12) = 8 then 4x = 20 and x = 5
Assuming the missing symbol there is an equals sign, then we have: y - 2x2 - 4x = 4 We can find it's vertex very easily by solving for y, and finding where it's derivative equals zero: y = 2x2 + 4x + 4 y' = 4x + 4 0 = 4x + 4 x = -1 So the vertex occurs Where x = -1. Now we can plug that back into the original equation to find y: y = 2x2 + 4x + 4 y = 2 - 4 + 4 y = 2 So the vertex is at the point (-1, 2)
It is: y = -4x+12
48
8x + 12 = 4x - 4 8x - 4x = -4 - 12 4x = -16 x = -4
If: 4x-4 = 12 Then: x = 4
4x-5=7 4x=12 x=3
4x + 6 = 6x - 12-4x -4x6 = 2x - 12+12 +1218 = 2xx=9
23 + 15x - 4x = 1215x - 4x = 12 -2311x = -11x= -1