Q: What is the x-coordinate of the vertex of y equals 4x - 12 - 3?

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The vertex of the positive parabola turns at point (-2, -11)

Need signs between terms.

It is: y = -4x+12

8x + 12 = 4x - 4 8x - 4x = -4 - 12 4x = -16 x = -4

4x-5=7 4x=12 x=3

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The vertex of the positive parabola turns at point (-2, -11)

Need signs between terms.

Assuming the missing symbol there is an equals sign, then we have: y - 2x2 - 4x = 4 We can find it's vertex very easily by solving for y, and finding where it's derivative equals zero: y = 2x2 + 4x + 4 y' = 4x + 4 0 = 4x + 4 x = -1 So the vertex occurs Where x = -1. Now we can plug that back into the original equation to find y: y = 2x2 + 4x + 4 y = 2 - 4 + 4 y = 2 So the vertex is at the point (-1, 2)

If: 4x-4 = 12 Then: x = 4

If: 4x+(-12) = 8 then 4x = 20 and x = 5

It is: y = -4x+12

8x + 12 = 4x - 4 8x - 4x = -4 - 12 4x = -16 x = -4

48

If: 4x-4 = 12 Then: x = 4

Differentiate and equate to zero Hence y = x^2 + 4x - 12 dy/dx = 2x + 4 = 0 2x = -4 x = -2 Hence y = (-2)^2 +4(-2) - 12 y = 4 - 8 - 12 y = - 16 Hence the vertex is (x,y,) = ( -2,-16)

4x + 6 = 6x - 12-4x -4x6 = 2x - 12+12 +1218 = 2xx=9

4x-5=7 4x=12 x=3