Best Answer

Assuming the missing symbol there is an equals sign, then we have:

y - 2x2 - 4x = 4

We can find it's vertex very easily by solving for y, and finding where it's derivative equals zero:

y = 2x2 + 4x + 4

y' = 4x + 4

0 = 4x + 4

x = -1

So the vertex occurs Where x = -1. Now we can plug that back into the original equation to find y:

y = 2x2 + 4x + 4

y = 2 - 4 + 4

y = 2

So the vertex is at the point (-1, 2)

Q: What is the vertex of the parabola y-2x2-4x 4?

Write your answer...

Submit

Still have questions?

Continue Learning about Other Math

The vertex would be the point where both sides of the parabola meet.

-2

To find the value of a in a parabola opening up or down subtract the y-value of the parabola at the vertex from the y-value of the point on the parabola that is one unit to the right of the vertex.

5

the vertex of a parabola is the 2 x-intercepts times-ed and then divided by two (if there is only 1 x-intercept then that is the vertex)

Related questions

The vertex would be the point where both sides of the parabola meet.

The coordinates will be at the point of the turn the parabola which is its vertex.

-2

3

5

To find the value of a in a parabola opening up or down subtract the y-value of the parabola at the vertex from the y-value of the point on the parabola that is one unit to the right of the vertex.

5

The vertex of a parabola doe not provide enough information to graph anything - other than the vertex!

The vertex is either the minimum (very bottom) or maximum (very top) of a parabola.

the vertex of a parabola is the 2 x-intercepts times-ed and then divided by two (if there is only 1 x-intercept then that is the vertex)

The vertex has a minimum value of (-4, -11)

The standard equation for a Parabola with is vertex at the origin (0,0) is, x2 = 4cy if the parabola opens vertically upwards/downwards, or y2 = 4cx when the parabola opens sideways. As the focus is at (0,6) then the focus is vertically above the vertex and we have an upward opening parabola. Note that c is the distance from the vertex to the focus and in this case has a value of 6 (a positive number). The equation is thus, x2 = 4*6y = 24y