Assuming the missing symbol there is an equals sign, then we have:
y - 2x2 - 4x = 4
We can find it's vertex very easily by solving for y, and finding where it's derivative equals zero:
y = 2x2 + 4x + 4
y' = 4x + 4
0 = 4x + 4
x = -1
So the vertex occurs Where x = -1. Now we can plug that back into the original equation to find y:
y = 2x2 + 4x + 4
y = 2 - 4 + 4
y = 2
So the vertex is at the point (-1, 2)
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-2
The vertex would be the point where both sides of the parabola meet.
To find the value of a in a parabola opening up or down subtract the y-value of the parabola at the vertex from the y-value of the point on the parabola that is one unit to the right of the vertex.
5
the vertex of a parabola is the 2 x-intercepts times-ed and then divided by two (if there is only 1 x-intercept then that is the vertex)