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Assuming the missing symbol there is an equals sign, then we have:

y - 2x2 - 4x = 4

We can find it's vertex very easily by solving for y, and finding where it's derivative equals zero:

y = 2x2 + 4x + 4

y' = 4x + 4

0 = 4x + 4

x = -1

So the vertex occurs Where x = -1. Now we can plug that back into the original equation to find y:

y = 2x2 + 4x + 4

y = 2 - 4 + 4

y = 2

So the vertex is at the point (-1, 2)

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Q: What is the vertex of the parabola y-2x2-4x 4?
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