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There are no operators visible before or after 24x.
GCD(15x, 24x) = 3x
5x^2-24x+11
3x2-24x-48 is not factorable.
The idea is to solve the equation -3x2 + 24x - 19 = 0. You can use the quadratic formula for this, using a = -3, b = 24, c = 19. Or complete the square since dividing by -3 will give us 8x, an even coefficient. -3x2 + 24x - 19 = 0 (add and subtract 48 to the left side) -3x2 + 24x -48 + 29 = 0 (subtract 29 to both sides, and factor out -3) -3(x2 - 8x + 16) = -29 (divide by -3 to both sides) (x - 4)2 = 29/3 x - 4 = ± √(29/3) (add 4 to both sides) x = 4 ± √(29/3) (multiply by 3/3 inside the radical, if you want to rationalize the denominator) x = 4 ± (√87)/3
3x - 24x + 5 + 3 = -21x + 8
twenty four times a number and add 19
0
3(2) + 24x + 48 = 0 6 + 24x + 48 = 0 24x + 54 = 0 24x + 54 - 54 = 0 - 54 24x = -54 24x/24 = -54/24 x = -9/4 x = -2 1/4
The answer is, 24x
(24x)^5 - (24x)^3 + (16x)^2 - 16 This can be simplified multiple ways: 1. pull (24x)^3 out of the first two terms and 16 out of the second two. (24x)^3((24x)^2-1) + 16(16x^2-1) 2. just pull 8 out of everything 8(3*(24x)^4-3*(24x)^2+32x^2-2) ...
GCD(15x, 24x) = 3x
24x - 7 = 17
24x^5 + 24x^3 = 24x^3(x^2 + 1)
5x^2-24x+11
3x2-24x-48 is not factorable.
-45
The GCF of 24x and 30x is 6x.