From the given information the straight line equation is: y = 7x-8
As written this is not a graphable thing. I does not represent a graphable equation because there is no "=" sign. Whatever the equation might be, the x intercept is found by setting y=0, which leaves you with an equation for x, which is the intercept.
If the equation of a line is in the form ax + by + c = 0 then the slope of the line will be -a/b.
If the slope m is given at a point (xo, yo) of a line, then the equation of the line is given by: y - yo = m(x - xo)
If you mean: y = 3.8x then the slope is 3.8 with no y intercept
0
From the given information the straight line equation is: y = 7x-8
As written this is not a graphable thing. I does not represent a graphable equation because there is no "=" sign. Whatever the equation might be, the x intercept is found by setting y=0, which leaves you with an equation for x, which is the intercept.
If the equation of a line is in the form ax + by + c = 0 then the slope of the line will be -a/b.
If the slope m is given at a point (xo, yo) of a line, then the equation of the line is given by: y - yo = m(x - xo)
Substitute the coordinates of the point into the equation of the line. If the equation is still valid then the point is on the line; if not then it is not.
If you mean: y = 3.8x then the slope is 3.8 with no y intercept
It would be perpendicular to a line with the equation Y = 1/8 X.
Write an equation in slope-intercept form for the line that passes through the given point and is parallel to the given line (-7,3); x=4
But it's not an equation because there is no equal sign and no points are given.
y - 7x is not an equation but an expression. It cannot, therefore, define a line.
if a line has a slope of -2 and a point on the line has coordinates of (3, -5) write an equation for the line in point slope form