Q: Writing an equation given a slope and a point?

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That will depend on the value of the slope which has not been given.

The straight line equation is: y = mx+c whereas m is the slope and c is the y intercept

Given a point P = (a,b) and slope m, the equation of a line through P with slope m is (y-b) = m(x-a)

Assuming the point is (3, -6) and the slope 1, the equation is x - y - 9 = 0

Given a point P(a,b) and slope m, the point slope equation is (y - b)/(x - a) = m

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p (2,-1) and slope 3

That will depend on the value of the slope which has not been given.

Use point-slope formula

Point: (-6, -2) Slope: 5 Equation: y = 5x+28

If you know the slope of the line that your equation is perpendicular too, you find the negative reciprocal of it and use it as the slope for the line. (negative reciprocal = flip the slope over and change its sign. Ex: a slope of 2 has a negative reciprocal of -1/2. ) Then you use the given point, and put your equation in point-slope form. The general equation for point slope form is Y-y1=m(x-x1) The y1 is the y coordinate of the given point. X1 is the x coordinate of the given point. M is the slope that you found earlier. You now have your equation. If you are asked to put it in slope intercept form, simply distribute the numbers and solve the equation for y.

The straight line equation is: y = mx+c whereas m is the slope and c is the y intercept

if a line has a slope of -2 and a point on the line has coordinates of (3, -5) write an equation for the line in point slope form

Given a point P = (a,b) and slope m, the equation of a line through P with slope m is (y-b) = m(x-a)

The equation is x = -7.

Assuming the point is (3, -6) and the slope 1, the equation is x - y - 9 = 0

Write the equation of a line in slope-intercept form that has a slope of -2 and passes through the point (2, -8).

Given a point P(a,b) and slope m, the point slope equation is (y - b)/(x - a) = m