horizontal line about which some part can be folded or rotated symmetrically or identically
X= -b / 2a
Letters that have more than one axis of symmetry include the letters "H," "I," "O," "X," and "Z." For example, "H" and "I" have both vertical and horizontal axes of symmetry, while "O" and "X" have infinite axes of symmetry. The letter "Z" has a diagonal axis of symmetry as well.
The axis of symmetry for a parabola of the form y = ax2 + bx + c is x = -b/2a So the axis is x = -2/2*(-3) or x=1/3
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The key letter in finding the axis of symmetry for a quadratic function in the standard form (y = ax^2 + bx + c) is (b). The axis of symmetry can be calculated using the formula (x = -\frac{b}{2a}), where (a) is the coefficient of (x^2). This formula provides the x-coordinate of the vertex of the parabola, which is also the line of symmetry.
The axis of symmetry is x = -2.
X= -b / 2a
Letters that have more than one axis of symmetry include the letters "H," "I," "O," "X," and "Z." For example, "H" and "I" have both vertical and horizontal axes of symmetry, while "O" and "X" have infinite axes of symmetry. The letter "Z" has a diagonal axis of symmetry as well.
The axis of symmetry for a parabola of the form y = ax2 + bx + c is x = -b/2a So the axis is x = -2/2*(-3) or x=1/3
18
The key letter in finding the axis of symmetry for a quadratic function in the standard form (y = ax^2 + bx + c) is (b). The axis of symmetry can be calculated using the formula (x = -\frac{b}{2a}), where (a) is the coefficient of (x^2). This formula provides the x-coordinate of the vertex of the parabola, which is also the line of symmetry.
Assume the expression is: y = x² - 6x + 5 Complete the squares to get: y = x² - 6x + 9 + 5 - 9 = (x - 3)² - 4 By the vertex form: y = a(x - h)² + k where x = h is the axis of symmetry x = 3 is the axis of symmetry.
It is x = 0.
If the function, or channel, or whatever you are reffering to has a axis of symmetry across both the y-axis and the x-axis
To find the axis of symmetry for the quadratic equation ( y = -x^2 + 2x - 4 ), you can use the formula ( x = -\frac{b}{2a} ), where ( a ) and ( b ) are the coefficients from the equation in standard form ( y = ax^2 + bx + c ). Here, ( a = -1 ) and ( b = 2 ). Plugging in the values, the axis of symmetry is ( x = -\frac{2}{2 \times -1} = 1 ). Thus, the axis of symmetry is ( x = 1 ).
Your equation must be in y=ax^2+bx+c form Then the equation is x= -b/2a That is how you find the axis of symmetry
axis of symmetry is x=0 Vertex is (0,0) So the answer is : YES