X= -b / 2a
The axis of symmetry for a parabola of the form y = ax2 + bx + c is x = -b/2a So the axis is x = -2/2*(-3) or x=1/3
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It is x = 0.
there are 4 axis of symmetry in a circle
The axis of symmetry is x = -2.
X= -b / 2a
The axis of symmetry for a parabola of the form y = ax2 + bx + c is x = -b/2a So the axis is x = -2/2*(-3) or x=1/3
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Assume the expression is: y = x² - 6x + 5 Complete the squares to get: y = x² - 6x + 9 + 5 - 9 = (x - 3)² - 4 By the vertex form: y = a(x - h)² + k where x = h is the axis of symmetry x = 3 is the axis of symmetry.
It is x = 0.
If the function, or channel, or whatever you are reffering to has a axis of symmetry across both the y-axis and the x-axis
axis of symmetry is x=0 Vertex is (0,0) So the answer is : YES
Your equation must be in y=ax^2+bx+c form Then the equation is x= -b/2a That is how you find the axis of symmetry
5 symmetry axis
Its extremum is on its axis of symmetry.
What is axis of symmetry? the axis of symmetry is a line that divides a planar figure into two congurent reflected halves