Your equation must be in y=ax^2+bx+c form
Then the equation is x= -b/2a
That is how you find the axis of symmetry
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Line of symmetry: x = 3
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x=-b/2a [negative B over 2A]
Assume the expression is: y = x² - 6x + 5 Complete the squares to get: y = x² - 6x + 9 + 5 - 9 = (x - 3)² - 4 By the vertex form: y = a(x - h)² + k where x = h is the axis of symmetry x = 3 is the axis of symmetry.
y = x2 + 8x - 7 a = 1, b = 8, c = -7 the equation of the axis of symmetry: x = -b/2a x = -8/(2*1) = -4