Line of symmetry: x = 3
D
x=-b/2a [negative B over 2A]
Assume the expression is: y = x² - 6x + 5 Complete the squares to get: y = x² - 6x + 9 + 5 - 9 = (x - 3)² - 4 By the vertex form: y = a(x - h)² + k where x = h is the axis of symmetry x = 3 is the axis of symmetry.
y = x2 + 8x - 7 a = 1, b = 8, c = -7 the equation of the axis of symmetry: x = -b/2a x = -8/(2*1) = -4
If a quadratic function has the points (-4,0) and (14,0), what is equation of the axis of symmetry?
There is no equation (nor inequality) in the question so there can be no graph - with or without an axis of symmetry.
-1
X=-b/2a
12 x 5 = 60
Line of symmetry: x = 3
D
How about y = (x - 2)2 = x2 - 4x + 4 ? That is the equation of a parabola whose axis of symmetry is the vertical line, x = 2. Its vertex is located at the point (2, 0).
Did you mean a parabola with equation y=3x^2? The line of symmetry is x=0 or the y-axis.
x=-b/2a [negative B over 2A]
First the formula is g(x)=ax2+bx+c First find where the parabola cuts the x axis Then find the equation of the axis of symmetry Then
Assume the expression is: y = x² - 6x + 5 Complete the squares to get: y = x² - 6x + 9 + 5 - 9 = (x - 3)² - 4 By the vertex form: y = a(x - h)² + k where x = h is the axis of symmetry x = 3 is the axis of symmetry.