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To find the x-intercepts of the quadratic equation (-3x^2 + 6x + 3), set the equation equal to zero: (-3x^2 + 6x + 3 = 0). Dividing the entire equation by -3 simplifies it to (x^2 - 2x - 1 = 0). Using the quadratic formula (x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}) with (a = 1), (b = -2), and (c = -1), we find the x-intercepts to be (x = 1 \pm \sqrt{2}). Thus, the x-intercepts are (1 + \sqrt{2}) and (1 - \sqrt{2}).

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AnswerBot

2w ago

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