3X2 + 6X + 9
3(X2 + 2 + 3)
-----------------------3 is a common factor of all terms
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6x-6x=0 so all you have left is -16 and there is nothing to factor. I am guessing you meant 6x2 -6x-16 which is 2(3x2 -2x-8) The factor pairs for 8 are 1,8 and 2,4. So let's try 1, 8. We know one of them has to be negative. We see it does not work and when we try 2 and 4 they do not work also. So we cannot factor (3x2 -2x-8) over the integers and we call it prime. The final answer is 2(3x2 -2x-8)
Not factorable
3x2 + 6x - 24First factor out any common factors of the three terms. In this case, each term is a multiple of 3. So,3x2 + 6x - 24 = 3(x2 + 2x - 8)Next, use the reverse FOIL method to factor the polynomial in the parenthesis (x2 + 2x - 8). x2 factors out to x * x:(x + ??)(x + ??)Now, we must find two numbers that add to get 2 (from the 2x) and multiply to get -8. Those numbers are -2 and 4. So,(x2 + 2x - 8) = (x - 2)(x + 4)So,3x2 + 6x - 24 = 3(x - 2)(x + 4)
3y plus 6x = 2
x2 plus 6x-2 equal -2x2 plus x ..=7x equal -3x2 ..4x=2x=2 answer ..check it if u dont want to trust ..Improved Answer:x2+6x-2 = -2x2+xx2+2x2+6x-x-2 = 03x2+5x-2 = 0(3x-1)(x+2) = 0x = 1/3 or x = -2The answer can be checked by using the quadratic equation formula.