What is the x intercept of x2-6x plus 8?

Answer 1

A function f crosses the x axis where f(x) = 0.

So the function f(x) = x^2-6x+8 crosses the x axis where x^2-6x+8 =0.

x^2-6x+8 can be factored:

(x + 4) (x -2) = 0

When x = -4, f(x) = 0.

and When x = 2, f(x) = 0.