If: 3x-5y+10 = 0 Then: -5y = -3x-10 And: y = 0.6x+2 in slope-intercept form
Yes, 3x = 5y is a linear function.
(4, -1)
3x-5y=15 The equation-5y=15-3x Subtract 3x from both sidesy=-3+.6x Divide both sides by -5
x=(-5y-1)/3
If: 3x-5y+10 = 0 Then: -5y = -3x-10 And: y = 0.6x+2 in slope-intercept form
3x+5y=48 5y=48-3x-3x+5y=12 -3x+(48-3x)=12-6x=-36x=65y=48-3(6)5y=30y=6(6,6)
(5, 1)
Yes, 3x = 5y is a linear function.
(4, -1)
no, 4x-3y=11x 3x-5y doesn't equal -11
no
3x + 5y = -1 2x - 5y = 16 Add the two equations: 5x = 15 or x = 3 Substitute for x in the first equation: 3*3 + 5y = -1 15 + 5y = -1 5y = -10 so y = -10/5 = -2 The solution is (x, y) = (3, -2)
X = -2(13 + y) / 3x = 5y / 4 - 1
3x-5y=15 The equation-5y=15-3x Subtract 3x from both sidesy=-3+.6x Divide both sides by -5
x = 5, y = 1
If: 3x-5y = 25 Then: -5y = -3x+25 And: y = 3/5x-5 So: slope is 3/5 or 0.6 and the y intercept is -5