If: 3x-5y+10 = 0 Then: -5y = -3x-10 And: y = 0.6x+2 in slope-intercept form
If: 2x+5y = 2 and -3x-y = -3Then it works out that: x = 1 and y = 0
x = 1, y = 0
(-5, 2)
3x - y = 0 5y = 15 5y = 15 Divide by '5' on both sides Hence y = 3 Substitute for 'y' in the first equation./ 3x - 3 = 0 3x = 3 Divide both sides by ;3; x = 1 So in ( x,y) form the answer is ( 1,3).
If: 3x-5y+10 = 0 Then: -5y = -3x-10 And: y = 0.6x+2 in slope-intercept form
X intercept is the value of X when Y = 0 -5Y + 3X = 12 ley Y = 0 3x = 12 x = 4
If: 2x+5y = 2 and -3x-y = -3Then it works out that: x = 1 and y = 0
-3x + 5y = -15At the x-intercept, y=0:-3x = -15 . . . . . x = 5At the y-intercept, x=0:5y = -15 . . . . . y = -3
x = 1, y = 0
x = 1, y = 0
The given expressions are: 5x + 5y = 30 3x - 5y = -30 Combine both equations to get: 5x + 3x + 5y - 5y = -30 + 30 8x = 0 Then: 8x/8 = 0/8 x = 0 Substitute that value for either of the expressions to get: 5(0) + 5y = 30 5y = 30 y = 30/5 y = 6 Therefore, the coordinates are x = 0 and y = 6.
The intercept of -3x + 5y - 2z = 60 are (-20, 0, 0), (0, 12, 0) and (0, 0, -30).
We cannot find out the y and x intercept for the equation 3x plus 5y equals -15 by a single equation . But , we can try a hit and trial method for the same . when x =0 y =-3. when y=0 x=-5.
(-5, 2)
3x - y = 0 5y = 15 5y = 15 Divide by '5' on both sides Hence y = 3 Substitute for 'y' in the first equation./ 3x - 3 = 0 3x = 3 Divide both sides by ;3; x = 1 So in ( x,y) form the answer is ( 1,3).
3x - 5y = 45At the y-intercept, x = 0.-5y = 45y = -9At the x-intercept, y = 0.3x = 45x = 15