y2 - 16y + 64 = 0
(y - 8)2 = 0
y - 8 = 0
y = 8
x2 + 12x - 64 = 0 ∴ (x + 16)(x - 4) = 0 ∴ x ∈ {4, -16}
15.625
66
64-3 equals = 61
5/8 of 64 equals 40. 5 x 64 =320. 320 divided by 8 = 40.
So the pattern would be 0 up to the 8 which equals 0. Next would be 1 up to the 7th which equals 1. Next the sequence would be 2 up to the 6th which equals 64, 3 up to the th5 which equals 243, 4 up to the 4th which equals 256, 5 up to the 3rd equals 125, 6 up to the 2nd equals 36, 7 up to the 1st equals 7, and 8 up to the 0 equals 1.
To find what number multiplied by 12 equals 64, you would divide 64 by 12. 64 divided by 12 equals 5.33 recurring. Therefore, 5.33 recurring times 12 equals 64.
No way that is true max number I can get is 64 (4x4x4+0)
How about: 8*8 = 64
16
Y =sqrt(4x^2 +64/16) I would, after factoring, say +/- 2; horizontally
0.1094