y2 - 16y + 64 = 0
(y - 8)2 = 0
y - 8 = 0
y = 8
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x2 + 12x - 64 = 0 ∴ (x + 16)(x - 4) = 0 ∴ x ∈ {4, -16}
15.625
66
5/8 of 64 equals 40. 5 x 64 =320. 320 divided by 8 = 40.
64-3 equals = 61
So the pattern would be 0 up to the 8 which equals 0. Next would be 1 up to the 7th which equals 1. Next the sequence would be 2 up to the 6th which equals 64, 3 up to the th5 which equals 243, 4 up to the 4th which equals 256, 5 up to the 3rd equals 125, 6 up to the 2nd equals 36, 7 up to the 1st equals 7, and 8 up to the 0 equals 1.
No way that is true max number I can get is 64 (4x4x4+0)
To find what number multiplied by 12 equals 64, you would divide 64 by 12. 64 divided by 12 equals 5.33 recurring. Therefore, 5.33 recurring times 12 equals 64.
Y =sqrt(4x^2 +64/16) I would, after factoring, say +/- 2; horizontally
How about: 8*8 = 64
16
(x - 16)(x + 4) = 0 so x = -4 or 16