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Find the y-intercepts of 16y squared equals 120x-225?
We are told: 16y2 = 120x - 225 The y-intercepts will happen where x equals zero, so we can say: 16y2 = 120(0) - 225 16y2 = -225 y2 = -225 / 16 y = √(-225 / 16) y = ±15i/4
Is x2-16y2 a prime?
No.
Factorise x2 - 16y2?
For a polynomial a2 - b2 = (a + b)(a - b).So for x2 - 16y2 ---> a = x, and b = 4y: (x + 4y)(x - 4y)
What is 4y squared equal to?
(4y)2 = 16y2
How do you factor 16y squared - 8y equals 0?
16y^2(8y)=0? Factor out an 8y to give you 8y(2y(2))=0 Use order of operations to give you 8y(4y)=0 Distribute to give you 32y=0 and ultimately the answer will be 0 If there is a missing plus or minus operator between 16y2 and the 8y, then it can be factorised by taking out common factors: 16y2 ± 8y = 0 ⇒ 8y(2y ± 1) = 0
How do you factor 9 - 16y2?
(3 - 4y)(3 + 4y)
How do you factor 64y3-1?
(4y - 1)(16y2 + 4y + 1)
Factor 3x2 plus 14xy plus 16y2?
(x + 2y)(3x + 8y)
How do you factor 8y3-16y2 plus 6y?
2y(2y - 1)(2y - 3)
How do you factor 8y3 -16y2 plus 6y?
2y(2y - 1)(2y - 3)
How do you factorize 9 multiplied by x square plus 24 multiplied by x and y plus 16 multiplied by y square?
9x2 + 24xy + 16y2 = 9x2 + 12xy + 12xy + 16y2 = 3x(3x + 4y) + 4y(3x + 4y) = (3x + 4y)*(3x + 4y) = (3x + 4y)2
Which is equal to square root of 48y2 Assume y is nonnegative?
sqrt(48y2) = sqrt(3*16y2) = sqrt(3)*4y = 6.928y (approx)
