Is the equation of a straight line with slope 2 and an intercept of (0,20).
Slope= -2/5 y-intercept is 20 x-intercept is 50
If as a straight line equation: 5x+2y = 20 then y = -2.5x+10 whereas -2.5 is the slope and 10 is the y intercept
y = -2x+10
x-intercept | -10 y-intercept | 4 slope | 2/5 = 0.4
Is the equation of a straight line with slope 2 and an intercept of (0,20).
-16
Slope= -2/5 y-intercept is 20 x-intercept is 50
-20
If as a straight line equation: 5x+2y = 20 then y = -2.5x+10 whereas -2.5 is the slope and 10 is the y intercept
y = -2x+10
5x - 2y = 20The x-intercept of a line is the point where its y-value is 0. When y=0, we get 5x = 20, or x=4. This means the coordinates of the x-intercept on this line are (4,0).
x-intercept | -10 y-intercept | 4 slope | 2/5 = 0.4
4x+2y = 20 2y = -4x+20 y = -2x+10
== == y = -x + 5
5x+4y = 20 4y = -5x+20 y = -5/4x+5 Therefore: slope is -5/4 and intercept is 5
Basically, the x-intercept is what x equals when y=0, and the y-intercept is what y equals when x=0. To find the x intercept, set y equal to 0. -5x+10(0)=20 -5x+0=20 -5x=20 divide both sides by -5 x=-4 so the x intercept is (-4,0) To find the y intercept, set x equal to 0. -5(0)+10y=20 0+10y=20 10y=20 divide both sides by 10 y=2 so the y intercept is (0,2)