y = -2x - 8
x-intercept is at y=0y=x^2+6x+80=x^2+6x+80=(x+4)(x+2)x=-4,-2x-intercepts are at (4,0) and (-2,0)
6x+3y = 8 3y = -6x+8 y = -3x+8/3 The slope of the line is -3
The quadratic expression x2+6x+8 when factorised equals (x+2)(x+4)
6x+8y = 12 8y = -6x+12 Divide all terms by 8:- y = -0.75x+1.5 which is now in slope intercept form
y = 6x+8 is already in slope intercept form
2y = -6x + 8 The y intercept occurs when x = 0 2y = 8 therefore y = 4
y = -2x - 8
x-intercept is at y=0y=x^2+6x+80=x^2+6x+80=(x+4)(x+2)x=-4,-2x-intercepts are at (4,0) and (-2,0)
6x+3y = 8 3y = -6x+8 y = -3x+8/3 The slope of the line is -3
The quadratic expression x2+6x+8 when factorised equals (x+2)(x+4)
6x+8y = 12 8y = -6x+12 Divide all terms by 8:- y = -0.75x+1.5 which is now in slope intercept form
6x + 8 = 13, 6x = 13 - 8, 6x = 5, x = 5/6
6X + 5Y = 8 subtract 6X from both sides 5Y = -6X + 8 divide both sides by 5 Y = -6/5X+ 8/5 now you have a line of slope -6/5 that intersects the Y axis at 8/5. (Solve for X to get X intercept)
The first line has slope = 6, so the parallel line must also have slope = 6: y = 6x + b. b is the y-intercept, but if you don't remember it:y-intercept = 8, means when x = 0, then y = 8, so substitute in and solve for b.8 = 6*0 + b --> b = 8. y = 6x + 8
y=6x-16 y=-2x+8
6x+4=52 6x=48 x=8