Need to put in function form. Y =mX + c 6X + 8Y = 12 8Y = - 6X + 12 Y = - 3/4X + 3/2 ----------------------- read off function m = - 3/4 ---------------------slope
3
6x plus 3y minus 2x plus 5y equals 4x plus 8y.
6x = 32 - 4y and 4y - 8 = 6x so 32 - 4y = 4y - 8 ie 40 = 8y so y = 5 and x = 2
hyperbola
Need to put in function form. Y =mX + c 6X + 8Y = 12 8Y = - 6X + 12 Y = - 3/4X + 3/2 ----------------------- read off function m = - 3/4 ---------------------slope
3
If you mean: 6x+8y = 12 then y = -0.75x+1.5 with the slope being -0.75 or -3/4 and the y intercept is 1.5 or 1 and a 1/2
2y = 6x - 8y = 3x - 4========m(slope) = 3=========
14
6x plus 3y minus 2x plus 5y equals 4x plus 8y.
6x = 32 - 4y and 4y - 8 = 6x so 32 - 4y = 4y - 8 ie 40 = 8y so y = 5 and x = 2
The answer depends on what the feasible region is and on what operator is between 6x and 8y.
hyperbola
6x-3y
It is: x = -3 and y = -6 or as (-3, -6)
Yes because the slope or gradient are the same 4/3