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S equals -10t2 plus vt plus k

This is one of the three formulae for motion. The standard form is S = ut + 1/2ft2.

S = distance, u = initial velocity, f = acceleration, t = time, k is unknown.

The equation in the question could thus be written, S = ut - 10t2 +k. This would imply that the acceleration is -10.

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Q: What is this S equals -10t2 plus vt plus k?
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