S equals -10t2 plus vt plus k
This is one of the three formulae for motion. The standard form is S = ut + 1/2ft2.
S = distance, u = initial velocity, f = acceleration, t = time, k is unknown.
The equation in the question could thus be written, S = ut - 10t2 +k. This would imply that the acceleration is -10.
16t2 + vt - S = 0 This is in the general form of the quadratic equation, and the general quadratic solution can be applied directly. t = [ (-v) plus or minus the square root of (v2 + 64S) ] all divided by 32.
s = -70
s = 20
s = -2 -4r
It is an equation in the single variable, s.
16t2 + vt - S = 0 This is in the general form of the quadratic equation, and the general quadratic solution can be applied directly. t = [ (-v) plus or minus the square root of (v2 + 64S) ] all divided by 32.
s = -70
4
v
s = 20
S=vt-16t2 solve for v is what I will assume you mean. first pull out the t S=t(v-16t) then devide by t S/t=v-16t Then add 16t to both sides S/t + 16t = v This can also be written as (S+16t2)/t = v
46
s = -2 -4r
It is an equation in the single variable, s.
S = {-5, 1}
yes and tom rules
wth??