Q: Q plus r equals s so t plus u equals?

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If P varies jointly as q, r and s - assume this is in direct proportion, then P âˆ qrs so P = kqrs where k is a constant.70 = k x 7 x 5 x 4 = 140k : k = 140/70 = 0.5When q = 2, r = 15 and s = 7 then,P = 0.5 x 2 x 15 x 7 = 105

pq-r, if p is 3, q is 4, and r is -6 is equal to 3 x 4 - (-6), which is equal to 12 + 6, which is equal to 18.

PQR P=2 Q=4 R=5 2 x 4 x 5 = 40

p(q + r) = pq + pr is an example of the distributive property.

You'd have no problem at all if it was [ 26 pigs + 1 quart + 1 rat + 4 quarts + 5 rats ]. You'd add up the quarts, and then you'd add up the rats. You do the same with p's, q's, and r's . 26p + q + r + 4q + 5r = 26p + 5q + 6r

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How many twelves can you put into 448 without going over? 37(37=q). You will get 444. subtract 444 from 448 and you get 4(4=r) So q=37 and r=4.

p + r + q + 175

=b+2h+r+x+z+q+a+p+l+f+g+d

g h plus r d g is the sister of (h plus (r is a sister of d)) g is the sister of h is the father of r is the sister of d so g is d's aunt.

so 26 = 4r so r = 6½

Starting with the information that is given: Two options, due to the lack of punctuation: a=1b=2z=26 -or- a=1 b=2 z=36 p=(not defined) q=(not defined) r=(not defined) Therefore, all we can assert from the given information is that p+q+r = p+q+r (the variables can be rearranged without altering the (unknown) value, because of the commutative property of addition. a, b and z are not used in the equation, so their values are irrelevant. p, q and r are not defined, so we cannot assume any value for any of the variables in the equation. Well, we could assume, but it would be just that - an assumption, and an unfounded assumption at that. There was not enough information provided to draw any more concrete conclusion.

Without prior knowledge of the value of q or r, it is impossible to calculate the answer to this equation.

If P varies jointly as q, r and s - assume this is in direct proportion, then P âˆ qrs so P = kqrs where k is a constant.70 = k x 7 x 5 x 4 = 140k : k = 140/70 = 0.5When q = 2, r = 15 and s = 7 then,P = 0.5 x 2 x 15 x 7 = 105

p + q + r = (2x - 9y) + (5y + 6 - 4x) + (3x + 3y - 5) = x - y + 1

pq-r, if p is 3, q is 4, and r is -6 is equal to 3 x 4 - (-6), which is equal to 12 + 6, which is equal to 18.

PQR P=2 Q=4 R=5 2 x 4 x 5 = 40