It would have been helpful if you had actually given "this" equation. But since you have not bothered to share that crucial bit of information, I cannot provide a more useful answer.
ax2 + bx + c = 0
The equation of the line is written in the standard form, y = mx+c
A standard form of a linear equation would be: ax + by = c
.983
The standard form of an equation is Ax + By = C. In this type of equation, x and y are variables while A, B, and C are integers.
ax2 + bx + c = 0
The equation of the line is written in the standard form, y = mx+c
A standard form of a linear equation would be: ax + by = c
.983
2X - y - 8 = 0the standard form of the equation is y = mx + chere you have to write the given equation in the standard form as in the form of y = mx + c2X - y - 8 = 0 - y -8 = -2x-y = -2x +8y = 2x -8so the standard form of the given equation is y = 2x - 8
The standard form of an equation is Ax + By = C. In this type of equation, x and y are variables while A, B, and C are integers.
The quadratic equation, in its standard form is: ax2 + bx + c = 0 where a, b and c are constants and a is not zero.
Solve the equation for ' y '.
The equation y - 4x - 1 can be rewritten in standard form as -4x + y = 1. In standard form, the equation is written as Ax + By = C, where A, B, and C are integers, and A is typically positive. This form is commonly used in mathematics and allows for easier comparison and manipulation of equations.
To put the equation (6y - 4 = 3x) in standard form, we first rearrange it to get all terms on one side. This gives us (3x - 6y + 4 = 0). The standard form is typically written as (Ax + By = C), so we can rewrite it as (3x - 6y = -4). Thus, the equation in standard form is (3x - 6y = -4).
It is already written in standard form.
To determine the form of a linear equation, it would depend on the specific equation provided. The rise-run form focuses on the change in y over the change in x (slope), the slope-intercept form is written as (y = mx + b), standard form is (Ax + By = C), and point-slope form is expressed as (y - y_1 = m(x - x_1)). Without seeing the actual equation, it's not possible to accurately identify its form.