Solve the equation for ' y '.
The equation of the line is of the form y = 3x + c where c is a constant. The point (4,9) is on the line, so substituting x=4, y=9 in the equation, 9 = 3*4 + c = 12 + c so c = -3 So the equation of the line is y = 3x - 3
In the equation y x-5 2 plus 16 the standard form of the equation is 13. You find the answer to this by finding the value of X.
It is: 2.63*106
Slope-intercept form: y=mx+bStandard form: Ax+By=CAx+By=C --> By=-Ax+C --> y=-Ax/B+C/BWell they might need a little more help than just formulas... here is an exampleStandard form hasax + by = c, where a, b, and c are integers.Slope-intercept form hasy = mx + bTo convert slope-intercept form to standard form, subtract mx from both sides of the equation.-mx + y = bIf m is a fraction, multiply the equation by its denominator.Exampley = 2/3x + 6 (slope-intercept form)-2/3x + y = 6 (after the subtractionof 2/3x)-2x + 3y = 18 (standard form, after multiplication by 3)
y = mx + b, just subtract mx to both sides -mx + y = b. If the slope is a fraction, it is nice to eliminate the denominator first, so go and multiply each term at both sides by the denominator. If both, the slope and the constant, are fractions, multiply each term at both sides by their least common denominator.
square
y = 2x + 1.
To convert a quadratic equation from standard form (ax^2 + bx + c) to factored form, you first need to find the roots of the equation by using the quadratic formula or factoring techniques. Once you have the roots, you can rewrite the equation as a product of linear factors, such as (x - r1)(x - r2), where r1 and r2 are the roots of the equation. This process allows you to express the quadratic equation in factored form, which can be useful for solving and graphing the equation.
the square
A standard form of a linear equation would be: ax + by = c
That already is in standard form.
The standard form of an equation is Ax + By = C. In this type of equation, x and y are variables while A, B, and C are integers.
The equation of the line is of the form y = 3x + c where c is a constant. The point (4,9) is on the line, so substituting x=4, y=9 in the equation, 9 = 3*4 + c = 12 + c so c = -3 So the equation of the line is y = 3x - 3
ax+by=c
the formula for standard form is Ax+By=C
Normally a quadratic equation will graph out into a parabola. The standard form is f(x)=a(x-h)2+k
In the equation y x-5 2 plus 16 the standard form of the equation is 13. You find the answer to this by finding the value of X.