Solve the equation for ' y '.
The equation of the line is of the form y = 3x + c where c is a constant. The point (4,9) is on the line, so substituting x=4, y=9 in the equation, 9 = 3*4 + c = 12 + c so c = -3 So the equation of the line is y = 3x - 3
In the equation y x-5 2 plus 16 the standard form of the equation is 13. You find the answer to this by finding the value of X.
It is: 2.63*106
Slope-intercept form: y=mx+bStandard form: Ax+By=CAx+By=C --> By=-Ax+C --> y=-Ax/B+C/BWell they might need a little more help than just formulas... here is an exampleStandard form hasax + by = c, where a, b, and c are integers.Slope-intercept form hasy = mx + bTo convert slope-intercept form to standard form, subtract mx from both sides of the equation.-mx + y = bIf m is a fraction, multiply the equation by its denominator.Exampley = 2/3x + 6 (slope-intercept form)-2/3x + y = 6 (after the subtractionof 2/3x)-2x + 3y = 18 (standard form, after multiplication by 3)
y = mx + b, just subtract mx to both sides -mx + y = b. If the slope is a fraction, it is nice to eliminate the denominator first, so go and multiply each term at both sides by the denominator. If both, the slope and the constant, are fractions, multiply each term at both sides by their least common denominator.
square
y = 2x + 1.
To convert a quadratic equation from standard form (ax^2 + bx + c) to factored form, you first need to find the roots of the equation by using the quadratic formula or factoring techniques. Once you have the roots, you can rewrite the equation as a product of linear factors, such as (x - r1)(x - r2), where r1 and r2 are the roots of the equation. This process allows you to express the quadratic equation in factored form, which can be useful for solving and graphing the equation.
the square
The standard form of the equation of a line is given by (Ax + By = C), where (A), (B), and (C) are integers, and (A) should be non-negative. In this form, (A) and (B) represent the coefficients of (x) and (y), respectively. To convert from slope-intercept form (y = mx + b) to standard form, you can rearrange the equation to fit the (Ax + By = C) structure.
A standard form of a linear equation would be: ax + by = c
In the context of standard form for a linear equation, which is typically expressed as (Ax + By = C), (A), (B), and (C) can indeed be negative numbers, including (A) being negative. However, it's common practice to write the standard form with (A) as a non-negative integer. If (A) is negative, you can multiply the entire equation by -1 to convert it to a standard form with a positive (A).
To convert a quadratic equation from vertex form, (y = a(x - h)^2 + k), to standard form, (y = ax^2 + bx + c), you need to expand the equation. Start by squaring the binomial: ( (x - h)^2 = x^2 - 2hx + h^2 ). Then, multiply by (a) and add (k) to obtain (y = ax^2 - 2ahx + (ah^2 + k)), where (b = -2ah) and (c = ah^2 + k). This results in the standard form of the quadratic equation.
To convert the equation ( y = 58x - 9 ) into standard form ( Ax + By = C ), we can rearrange it. First, subtract ( 58x ) from both sides to get ( -58x + y = -9 ). To have integer coefficients, we can multiply the entire equation by -1, resulting in ( 58x - y = 9 ). Thus, the standard form of the equation is ( 58x - y = 9 ).
That already is in standard form.
The standard form of an equation is Ax + By = C. In this type of equation, x and y are variables while A, B, and C are integers.
To convert a vertex form equation of a parabola, given as ( y = a(x - h)^2 + k ), to standard form ( y = ax^2 + bx + c ), expand the squared term: ( (x - h)^2 = x^2 - 2hx + h^2 ). Then, multiply through by ( a ) and combine like terms: ( y = ax^2 - 2ahx + (ah^2 + k) ). The coefficients ( a ), ( b = -2ah ), and ( c = ah^2 + k ) represent the standard form parameters.