(10)(2x)
2xa/b
2ab
The two numbers are 10 and 14.
10n
Twice that number!
(10)(2x)
5 and 10
The product of twice "a" and "b" can be expressed as: 2ab In this expression, "a" and "b" are variables that represent numerical values. Multiplying "a" and "b" gives their product, and then multiplying the result by 2 gives twice that product.
x=ab
10: 3n = 2(n + 5); 3n = 2n + 10; (subtract 2n from each side) n = 10.
2ab
2xa/b
2ab
The two numbers are 10 and 14.
The current in the secondary when the voltage is twice the primary will be one half of the primary. The current in the primary when the voltage is twice the secondary will be twice the secondary.
The answer would be 10 12 and 14... 14 x 3 = 42 and 2(10 + 12) = 44. So the product of the largest integer and three is two less than twice the sum of the lower integers.