The integers are 14 and 7.
One (negative) is preceded by a - sign and the other (positive) is not. Negative integers have values less than zero, whereas positive integers have values greater than zero. If a positive and negative integer are made up of the same digits and in the same order (e.g., 2 and -2, or 896 and -896), then when added together they will equal zero. If, however, one is subtracted from the other, then they will equal twice the number from which the other is subtracted.
y=2x+5 xy=52 x(2x+5)=52 2x2+5x-52=0 (2x+13)(x-4)=0 x=-6.5 or x=4 Since you specified positive integers, x=4. y=2*4+5=13 So, the two numbers are 13 and 4.
Let one integer be n, then the other is 2n + 3 and n(2n + 3) = 90; solve this last equation for n: n(2n + 3) = 90 ⇒ 2n2 + 3n - 90 = 0 ⇒ (2n + 15)(n - 6) = 0 ⇒ n = 6 or n = -7.5 As n must be a (positive) integer, the solution n = -7.5 can be ignored, leaving n = 6, giving 2n + 3 = 15. Thus the two positive integers are 6 and 15.
no one wants to know the answer. its freaking math
The integers are 14 and 7.
The two integers are 7 and 14. 7 x 14 = 98.
3 x 5 = 15 3 + 8 = 8 (15 + 1) / 2 = 8 Therefore, the two numbers are 3 and 5.
The answer would be 10 12 and 14... 14 x 3 = 42 and 2(10 + 12) = 44. So the product of the largest integer and three is two less than twice the sum of the lower integers.
4
One (negative) is preceded by a - sign and the other (positive) is not. Negative integers have values less than zero, whereas positive integers have values greater than zero. If a positive and negative integer are made up of the same digits and in the same order (e.g., 2 and -2, or 896 and -896), then when added together they will equal zero. If, however, one is subtracted from the other, then they will equal twice the number from which the other is subtracted.
y=2x+5 xy=52 x(2x+5)=52 2x2+5x-52=0 (2x+13)(x-4)=0 x=-6.5 or x=4 Since you specified positive integers, x=4. y=2*4+5=13 So, the two numbers are 13 and 4.
Let one integer be n, then the other is 2n + 3 and n(2n + 3) = 90; solve this last equation for n: n(2n + 3) = 90 ⇒ 2n2 + 3n - 90 = 0 ⇒ (2n + 15)(n - 6) = 0 ⇒ n = 6 or n = -7.5 As n must be a (positive) integer, the solution n = -7.5 can be ignored, leaving n = 6, giving 2n + 3 = 15. Thus the two positive integers are 6 and 15.
They are both evenThey each have 2 digitsFor both numbers the second digit is twice the first digitThey are both positive integers
1. They are positive integers.2. They are less than 20.3. When written out as word, in English, the letter eappears at least twice.
There are twelve instances where the integers from 1 to 200 contain the digit 1 at least twice:-11,101,110,111,121,131,141,151,161,171,181,191.
No, it is not. A perfect square is the product of two equal integers; i.e. 9 is a perfect square. It can be expressed as 3*3. There is no number that when multiplied twice equals 50.