5 and 10
The integers are 14 and 7.
One (negative) is preceded by a - sign and the other (positive) is not. Negative integers have values less than zero, whereas positive integers have values greater than zero. If a positive and negative integer are made up of the same digits and in the same order (e.g., 2 and -2, or 896 and -896), then when added together they will equal zero. If, however, one is subtracted from the other, then they will equal twice the number from which the other is subtracted.
y=2x+5 xy=52 x(2x+5)=52 2x2+5x-52=0 (2x+13)(x-4)=0 x=-6.5 or x=4 Since you specified positive integers, x=4. y=2*4+5=13 So, the two numbers are 13 and 4.
Let one integer be n, then the other is 2n + 3 and n(2n + 3) = 90; solve this last equation for n: n(2n + 3) = 90 ⇒ 2n2 + 3n - 90 = 0 ⇒ (2n + 15)(n - 6) = 0 ⇒ n = 6 or n = -7.5 As n must be a (positive) integer, the solution n = -7.5 can be ignored, leaving n = 6, giving 2n + 3 = 15. Thus the two positive integers are 6 and 15.
no one wants to know the answer. its freaking math
The integers are 14 and 7.
The two integers are 7 and 14. 7 x 14 = 98.
3 x 5 = 15 3 + 8 = 8 (15 + 1) / 2 = 8 Therefore, the two numbers are 3 and 5.
The answer would be 10 12 and 14... 14 x 3 = 42 and 2(10 + 12) = 44. So the product of the largest integer and three is two less than twice the sum of the lower integers.
4
One (negative) is preceded by a - sign and the other (positive) is not. Negative integers have values less than zero, whereas positive integers have values greater than zero. If a positive and negative integer are made up of the same digits and in the same order (e.g., 2 and -2, or 896 and -896), then when added together they will equal zero. If, however, one is subtracted from the other, then they will equal twice the number from which the other is subtracted.
y=2x+5 xy=52 x(2x+5)=52 2x2+5x-52=0 (2x+13)(x-4)=0 x=-6.5 or x=4 Since you specified positive integers, x=4. y=2*4+5=13 So, the two numbers are 13 and 4.
Let one integer be n, then the other is 2n + 3 and n(2n + 3) = 90; solve this last equation for n: n(2n + 3) = 90 ⇒ 2n2 + 3n - 90 = 0 ⇒ (2n + 15)(n - 6) = 0 ⇒ n = 6 or n = -7.5 As n must be a (positive) integer, the solution n = -7.5 can be ignored, leaving n = 6, giving 2n + 3 = 15. Thus the two positive integers are 6 and 15.
They are both evenThey each have 2 digitsFor both numbers the second digit is twice the first digitThey are both positive integers
There are twelve instances where the integers from 1 to 200 contain the digit 1 at least twice:-11,101,110,111,121,131,141,151,161,171,181,191.
1. They are positive integers.2. They are less than 20.3. When written out as word, in English, the letter eappears at least twice.
No, it is not. A perfect square is the product of two equal integers; i.e. 9 is a perfect square. It can be expressed as 3*3. There is no number that when multiplied twice equals 50.