What pressure or are you asking drainage THEN What pitch are you using
To determine how much water a 6-inch pipe can hold, you need to calculate its volume based on its length. The volume (in gallons) can be found using the formula for the volume of a cylinder: ( V = \pi r^2 h ), where ( r ) is the radius (3 inches for a 6-inch pipe) and ( h ) is the length of the pipe in inches. For example, a 10-foot (120-inch) length of a 6-inch pipe would hold about 18.9 gallons of water.
To calculate the amount of concrete needed to fill a 50-foot long, 6-inch diameter pipe, first determine the volume of the pipe. The formula for the volume of a cylinder is ( V = \pi r^2 h ), where ( r ) is the radius and ( h ) is the height (or length). The radius of a 6-inch pipe is 3 inches (0.25 feet), so the volume is approximately ( V = \pi (0.25^2)(50) ), which equals about 9.82 cubic feet. Thus, you would need approximately 9.82 cubic feet of concrete to fill the pipe.
For laminar flow? For a full pipe? for a 3/4-full pipe? For a 1/2-full pipe? It all makes quite a difference. Please repost your question with a little more information. It would also help to for us to know the coefficient of friction of the inside of the pipe.
Assuming cylinder: volume = area of circle * length area of circle = pi*radius**2 radius = circumference/(2*pi) radius = diameter/2 if 24 inch is circumference: volume = pi*(24/(2*pi))**2 * 12 volume = 144/pi*12 volume = 1728/pi inch**3 if 24 inch is diameter: volume = pi*(24/2)**2 * 12 volume = pi*144*12 volume = pi*1728 inch**3 if 24 inch is radius: volume = pi*24**2 * 12 volume = pi*576*12 volume = pi*6912 inch**3 if 24 in
0.3672 gallon per foot of pipe.
The volume of a 3-inch pipe that is 1,000 feet long is: 49.09 cubic feet.
The volume of one foot of 3-inch PVC pipe is: 84.82 cubic inches. In terms of liquid, this equates to about 0.3672 (US) gallons or 47 fluid ounces for that section of pipe.
4324
To determine how much water a 6-inch pipe can hold, you need to calculate its volume based on its length. The volume (in gallons) can be found using the formula for the volume of a cylinder: ( V = \pi r^2 h ), where ( r ) is the radius (3 inches for a 6-inch pipe) and ( h ) is the length of the pipe in inches. For example, a 10-foot (120-inch) length of a 6-inch pipe would hold about 18.9 gallons of water.
what is the discharge flow of 10m/s passing from 2ft pipe
3 inch (inside diameter) pipe = 0.25 feet. Radius = 0.125 ft Cross section area = pi*(0.125 ft)2 = pi * 0.015625 ft2 . Multiply by 80 ft = pi * 1.25 cubic feet = 3.926990817 cubic feet x 7.480517578 (US gallons / cubic ft) = 29.37592384 US gallons.
That's 3/4" pipe, not 3.4" prehaps it would deliver more pressure through the 1/2 inch pipe than 3/4 inch. 3/4" pipe will be less restrictive over the course of the run. Otherwise, no. 1/2" Copper Pipe will do fine, since it has a smoother bore, less restrictive, no lime and rust build-up. The only reason for you to use 3/4" pipe is if you want more volume. The pressure remains the same.
In order to effectively answer this question more factors would need to be known. The most important factor being the type of liquid flowing through the pipe. Different liquids have a different rate of flow, even with varying elevations.
The pipe's volume is the product of its cross-sectional area and its length. The area of a circle is pi*(radius)^2, so in this case pi*9sq.in. or about 28.3 square inches. Multiply this area by the length of pipe you are using to obtain a volume. A 10 foot length of 6 inch pipe will have 3393 cubic inches of volume or 1.96 cubic feet, or 14.7 US Gallons.
The size of sprinkler pipe you should use for your irrigation system depends on the water flow and pressure needed. Generally, a 1-inch pipe is recommended for larger systems or areas with high water demand, while a 3/4-inch pipe is suitable for smaller systems or areas with lower water demand. It is important to consider factors such as water pressure, flow rate, and the number of sprinkler heads when choosing the pipe size for your irrigation system.
pi*radius2*length
54 times MORE volume