168
x2+12x+28Improved Answer:--x2+12x+28 = (-x+14)(x+2) when factored
x2+12x+5 = 3 x2+12x+5-3 = 0 x2+12x+2 = 0
x2-12x+20=0you can factor this equation into:(x-10)(x-2)=0set each factor equal to zero & solve for x to get:x=10 & x=2
x2 + 12x - 64 = 0 ∴ (x + 16)(x - 4) = 0 ∴ x ∈ {4, -16}
x + 12x + 20 = (x + 10)(x + 2)
168
(x + 10)(x + 2)
x2+12x+28Improved Answer:--x2+12x+28 = (-x+14)(x+2) when factored
x2+12x+5 = 3 x2+12x+5-3 = 0 x2+12x+2 = 0
x2 + 12x + 27 = (x + 9)(x + 3)
x2-12x+36 = (x-6)2
x2 + 12x + 32 = (x + 8)(x + 4)
x2 + 12x + 32 = (x + 4)(x + 8)
3x3+12x = 3x(x2+4)
x2-12x+35 = (x-5)(x-7)
x2 + 12x - 11 = x2 + 12x + (12/2)2 - (12/2)2 - 11 = (x + 6)2 - 47