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Q: What is the answer to completing the square to x2 plus 12x-11?

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x2 + 8x - 2 = 0 => x2 + 8x = 2 => x2 + 8x + 16 = 2 + 16 = 18 => (x + 4)2 = 18 => x + 4 = +or- sqrt(18) = +or- 3*sqrt(2) so x = -4 +or- 3*sqrt(2)

x2 + 4x + 1 = 0 add and subtract 3 to both sides to complete the square x2 + 4x + 4 = 3 form the square (x + 2)2 = 3 take the square root of both sides x + 2 = ± √3 subtract 2 to both sides x = -2 ± √3

(x-y)2 is a square so (x-y)2 >= 0 expanding, x2 - 2xy + y2 >= 0 so x2 + y2 >= 2xy or 2xy <= x2 + y2

144

x2+6x-7 = 0 (x+3)2-7 = 0 (x+3)2-7-9 = 0 (x+3)2 = 16 x+3 = + or - 4 x = - 3 + or - 4 x = 1 or -7

Related questions

ask jesus.

(x+8)^2=105

No because the discriminant of the given quadratic expression is less than zero.

X2+11x+11 = 7x+9 X2+11x-7x+11-9 = 0 x2+4x+2 = 0 Solve as a quadratic equation by using the quadratic equation formula or by completing the square: x = -2 + or - the square root of 2

y = x2 - 6x + 2 y = x2 - 6x + 9 - 7 y = (x - 3)2 - 7

x2 + 6x = 7 ⇒ x2 + 6x + 9 = 7 + 9 ⇒ (x + 3)2 = 16 ⇒ x + 3 = ±4 ⇒ x = -7 or 1

No.

Plus or minus the base. If the base is X and you square it, you get X2. If you take the square root of that, you get Plus or Minus X. This is because X*X equals X2 and -X*-X also equals X2.

Since there are only terms in x2 and constants, but none in x, completing the square is not an option! x2 - 14 = 7 x2 = 21 and so x2 = sqrt(21)

x2 + 20x +0 =30 [(20/2)2 =100] x2 + 20x + 100 =30 +100 √(x+10)2=√130 x+10=√130 x= −10+√130 √ means square root

If you aren't dealing with algebra, such as x2+3x+21, then completing the square wont be able to solve the porblem, however if you are using algebra, and you cannot factorise, then completing the square will always work

(X-4)^2=55

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