x3+3x2+3x+2 divided by x+2 equals x2+x+1
x2 + 3x + 2 factors into (x + 1) (x + 2)
x2 + 3x + 7 = 5 ∴ x2 + 3x + 2 = 0 ∴ (x + 1)(x + 2) = 0 ∴ x ∈ {-2, -1}
-2
(x - 1)(x - 2)
x3+3x2+3x+2 divided by x+2 equals x2+x+1
(3x4 + 2x3 - x2 - x - 6)/(x2 + 1)= 3x2 + 2x - 4 + (-3x - 2)/(x2 + 1)= 3x2 + 2x - 4 - (3x + 2)/(x2 + 1)where the quotient is 3x2 + 2x - 4 and the remainder is -(3x + 2).
x2 + 3x + 2 factors into (x + 1) (x + 2)
x2 + 3x + 7 = 5 ∴ x2 + 3x + 2 = 0 ∴ (x + 1)(x + 2) = 0 ∴ x ∈ {-2, -1}
x = 2
-2
(x - 1)(x - 2)
3x-1 = 11 3x = 11+1 3x = 12 x = 4 Therefore: x2+2 = 18
(12x2 + 18) / (3x2 + 6) = (4x2 + 6) / (x2 + 2)
Yes:- x2+3x+2 = 30 X2+3x+2-30 = 0 x2+3x-28 = 0 (x-4)(x+7) = 0 x = 4 or x = -7
(3x - 5x) + (x2 - 6x2) = -2x -5x2 = -x(2 + 5x)
x2+3x-10 = (x+5)(x-2) when factored