Multiply out the factors and then you can check: (x + 2)(x + 3) = x² + 3x + 2x + 6 = x² + 5x + 6 ≠ x² + 3x + 4 Therefore False.
That factors to (x + 5)(3x + 2)
20x2 - 3x + 10 does not have any real factors.
(2x + 7)(x - 2)
As written, that's 3x^3 - 12x which factors to 3x(x - 2)(x + 2)
6x2 + 14x -12 = (3x - 2) (2x + 6). There they are.
If that's -9x^3 - 3x^2 + 3x + 1, that factors to (1 - 3x^2)(1 + 3x)
3X + 8You don't factor this as there are no common factors.
3x2 + 4x factors to x(3x + 4)
Multiply out the factors and then you can check: (x + 2)(x + 3) = x² + 3x + 2x + 6 = x² + 5x + 6 ≠ x² + 3x + 4 Therefore False.
That factors to (x + 5)(3x + 2)
3x+21x+9x=33x. Break it apart. The factor of x is x and the factors of 33 are 3 and 11. Therefore, the factors of 3x+21x+9x are 3, 11, and x.
9x^2 +6 +1 is (3x+1)(3x+1) when factored
20x2 - 3x + 10 does not have any real factors.
(x + 4)(3x - 5)
3(4x2 - x + 2)
The factors are [3x + 5 - 2*sqrt(10)] and [3x 5 + 2*sqrt(10)].