x2-5x+4 = (x-1)(x-4) when factored
x2 + 4x - 9 = 5x + 3 ∴ x2 - x - 12 = 0 ∴ (x + 3)(x - 4) = 0 ∴ x ∈ {-3, 4}
-x2 + 5x - 4 = 0. Then, x2 - 5x + 4 = (x - 4)(x - 1) = 0; whence, x = 1 or 4. Checking, -1 + 5 - 4 = 0; and -16 + 20 - 4 = 0.
The factors of x2 + 5x + 4 would be (x + 1) and (x + 4)
x2+4x-9 = 5x+3 x2+4x-5x-9-3 = 0 x2-x-12 = 0 (x+3)(x-4) = 0 x = -3 or x = 4
x2-5x+4 = (x-1)(x-4) when factored
x2-5x+4 = (x-1)(x-4) when factord
(x + 4)(x + 1)
x2 + 4x - 9 = 5x + 3 ∴ x2 - x - 12 = 0 ∴ (x + 3)(x - 4) = 0 ∴ x ∈ {-3, 4}
-x2 + 5x - 4 = 0. Then, x2 - 5x + 4 = (x - 4)(x - 1) = 0; whence, x = 1 or 4. Checking, -1 + 5 - 4 = 0; and -16 + 20 - 4 = 0.
The factors of x2 + 5x + 4 would be (x + 1) and (x + 4)
x2+4x-9 = 5x+3 x2+4x-5x-9-3 = 0 x2-x-12 = 0 (x+3)(x-4) = 0 x = -3 or x = 4
x2 + 5x - 120 can not be factored.
(x-1)(x-4)
x2 + 5x + 6 = (x + 2)(x + 3)
2x + 5x = 7x
x2+5y+4 (i have no idea but)x2+5x+4 = (x+4)(x+1)