x2 + 8x - 9 = 0(x + 9) (x - 1) = 0(x + 9) = 0 . . . . . x = -9(x - 1) = 0 . . . . . x = 1
16
0
x = 9 some number that when you take NOTHING away from it is "9"
x2 + 14x + 45 = 0 => x2 + 9x + 5x + 45 = 0 => x(x + 9) + 5(x + 9) = 0 (x + 9)(x + 5) = 0 so that x = -5 or x = -9
x - 9 = 0 x - 9 = 0 x - 9 = 0 x - 9 = 0
x2 + 8x - 9 = 0(x + 9) (x - 1) = 0(x + 9) = 0 . . . . . x = -9(x - 1) = 0 . . . . . x = 1
y=x+9 y'=1 x+9=0 x=-9 y=-9+9 y=0
16
x * x - 9 = 0 PEMDAS = Multiplication first. What multiplied it self equals nine? 3. So x = 3
0
x = 9 some number that when you take NOTHING away from it is "9"
18. 9 x 0 = 0 S0, 9 + 0 + 9 = 18
x2 + 14x + 45 = 0 => x2 + 9x + 5x + 45 = 0 => x(x + 9) + 5(x + 9) = 0 (x + 9)(x + 5) = 0 so that x = -5 or x = -9
5x - 9 = 4x 5x - 4x - 9 = 4x - 4x x - 9 = 0 x - 9 + 9 = 0 + 9 x = 9
x2 + 9 = 10x x2 - 10x + 9 = 0. (x - 9)(x - 1) = 0. Therefore, x = 1 or 9.
(x-3)(x-9) = 0