just solve for x. 1) add 3y6 to both sides 2x=3y6 2) divide both sides by 2 to get x by itself: x=3y6/2
3x + x + 10 + x = 5x + 10
5x-3x+x+8 = 2x+1+x+x 3x+8 = 4x+1 3x-4x = 1-8 -x = -7 x=7 Hope that helps.
3x+5<x+11 3x<6 x<2
x3+3x2+3x+2 divided by x+2 equals x2+x+1
3x2+6xy+3y2= 3(x2+2xy+y2)= 3(x+y)2
X2+y2=25 (x-8)2+y2 =41
just solve for x. 1) add 3y6 to both sides 2x=3y6 2) divide both sides by 2 to get x by itself: x=3y6/2
3x + x + 10 + x = 5x + 10
9y-81=9*(y-9)
3a(3x - 2y)(3x - 2y)(3x - 2y) or 3a times (3x - 2y) to the third power
If you mean: -x+3y = 6 and x+3y = 18 then by substitution x = 6 and y = 4
y2=-x2-8x+6
5x-3x+x+8 = 2x+1+x+x 3x+8 = 4x+1 3x-4x = 1-8 -x = -7 x=7 Hope that helps.
-x + 3x = 2x
3x+5<x+11 3x<6 x<2
x3+3x2+3x+2 divided by x+2 equals x2+x+1