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well what we will do here is simplify the equation.

(x2+2x-15) / (x+5)

factor the numerator ----> [(x-3)(x+5)] / (x+5)

one of the factors in

numerator and the ----> [(x-3)(x+5)] / (x+5)

denominator cancel out

so you are left with the

simplified expression ----> (x-3)

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15y ago

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