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What is the answer to x-ab?
x-ab=0 x=ab
How do you solve a plus ab?
What is it you want to solve? You can factor it, taking out the common factor, "a". Thus, a + ab = a(1 + b). Or, if you want to convert it to a number, you can only do this if you know the values for "a" and "b". In this case, replace the values, and do the calculation.
Use Boolean algebra to simplify the logic function and realize the given function and minimized function using discrete gates. f equals ab c plus abc plus ac plus bc plus abC.?
Do you mean F = abc + abc + ac + bc + abc' ? *x+x = x F = abc + ac + bc + abc' *Rearranging F = abc + abc' + ab + bc *Factoring out ab F = ab(c+c') + ab + bc *x+x' = 1 F = ab + ab + bc *x+x = x F = bc
Can someone explain how to get x by itself in the equation x over a plus x over b equals 1 I know there answer is ab over a plus b but i don't know why?
x/a + x/b = 1Taking x as a common factor: x*(1/a + 1/b) = 1Adding the fractional parts x*(b/ab + a/ab) = 1or x*[(b + a)/ab] = 1Multiply both sides by (a+b)/abx = (a+b)/abAnother Approuch:-x/a+x/b = 1Multiply all terms by ab to eliminate the fractions:bx+ax = abFactorise:x(a+b) = abDivide both sides by (a+b):x = ab/(a+b)
How many ways can you arrange 5 items if two have to be next to each other?
There are 48 possibilities where 2 of 5 items must be adjacent.If you have 5 items, and they can be arranged in any order, there are 1205 x 4 x 3 x 2 ways to arrange them, for example ABCDE, ABCED, and so forth.However, if any two need to be placed next to each other, the number of variations is reduced to [4 x 3 x 2] x2 (=48), where there are only 4 separate "units" arranged, but the double-unit can appear with either of the pair first.For example, if A and B must be together, you have 24 possibilities:(AB)CDE(AB)CED(AB)DCE(AB)DEC(AB)EDC(AB)ECDC(AB)DEC(AB)EDD(AB)CED(AB)ECE(AB)CDE(AB)DCCD(AB)EDC(AB)ECE(AB)DEC(AB)DDE(AB)CED(AB)CCDE(AB)CED(AB)DEC(AB)DCE(AB)EDC(AB)ECD(AB)and another 24 where (AB) is replaced by (BA).
