x-ab=0 x=ab
What is it you want to solve? You can factor it, taking out the common factor, "a". Thus, a + ab = a(1 + b). Or, if you want to convert it to a number, you can only do this if you know the values for "a" and "b". In this case, replace the values, and do the calculation.
Do you mean F = abc + abc + ac + bc + abc' ? *x+x = x F = abc + ac + bc + abc' *Rearranging F = abc + abc' + ab + bc *Factoring out ab F = ab(c+c') + ab + bc *x+x' = 1 F = ab + ab + bc *x+x = x F = bc
x/a + x/b = 1Taking x as a common factor: x*(1/a + 1/b) = 1Adding the fractional parts x*(b/ab + a/ab) = 1or x*[(b + a)/ab] = 1Multiply both sides by (a+b)/abx = (a+b)/abAnother Approuch:-x/a+x/b = 1Multiply all terms by ab to eliminate the fractions:bx+ax = abFactorise:x(a+b) = abDivide both sides by (a+b):x = ab/(a+b)
There are 48 possibilities where 2 of 5 items must be adjacent.If you have 5 items, and they can be arranged in any order, there are 1205 x 4 x 3 x 2 ways to arrange them, for example ABCDE, ABCED, and so forth.However, if any two need to be placed next to each other, the number of variations is reduced to [4 x 3 x 2] x2 (=48), where there are only 4 separate "units" arranged, but the double-unit can appear with either of the pair first.For example, if A and B must be together, you have 24 possibilities:(AB)CDE(AB)CED(AB)DCE(AB)DEC(AB)EDC(AB)ECDC(AB)DEC(AB)EDD(AB)CED(AB)ECE(AB)CDE(AB)DCCD(AB)EDC(AB)ECE(AB)DEC(AB)DDE(AB)CED(AB)CCDE(AB)CED(AB)DEC(AB)DCE(AB)EDC(AB)ECD(AB)and another 24 where (AB) is replaced by (BA).
(a x b)^b =ab x b^2 =ab^3
x-ab=0 x=ab
Here is a proof. Let a and b be any two real numbers. Consider the number x defined as x = ab + (-a)(b) + (-a)(-b). We can write this out differently as x = ab + (-a)[ (b) + (-b) ] Then, by factoring out -a , we find that x= ab + (-a)(0) = ab + 0 = ab. Also, x = [ a + (-a) ]b + (-a)(-b) And by factoring out b, we find that x=0 * b + (-a)(-b) = 0 + (-a)(-b) = (-a)(-b). Therefore x = ab and x = (-a)(-b) Then, by the transitivity of equality, we have ab = (-a)(-b).
x-ab=0 x=ab
x2+bx+ax+ab = x2+ax+bx+ab = x(x+a)+b(x+a) = (x+a)(x+b)
x = ab x = 21*37 x = 777
A number a multiplied b times (so a x a is b=2, a x a x a is b=3, a x a x a x a is b = 4, and so on) is written as ab. Since 2 is multiplied 4 times, you have 24.
ab * -b = -ab^-2
What is it you want to solve? You can factor it, taking out the common factor, "a". Thus, a + ab = a(1 + b). Or, if you want to convert it to a number, you can only do this if you know the values for "a" and "b". In this case, replace the values, and do the calculation.
2m x 4n
Do you mean F = abc + abc + ac + bc + abc' ? *x+x = x F = abc + ac + bc + abc' *Rearranging F = abc + abc' + ab + bc *Factoring out ab F = ab(c+c') + ab + bc *x+x' = 1 F = ab + ab + bc *x+x = x F = bc
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