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x2-8x=-6
Add ((1/2)8)2 to both sides (add 16 to both sides):
x2-8x+16=10
Factor the left side:
(x-4)2=10
Take the square root of both sides
x-4 = ±√(10)
Make two equations because of the plus or minus:
x-4 = √(10) and x-4 = -√(10)
Add four to both sides (works for both equations):
x = 4+√(10) and x = 4-√(10)
Add your answer:
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What is x-squared minus 8x equals negative 15?
x=3
What is x squared minus 8x equals negative 12?
If: x^2 -8x = -12 then x^2-8x+12 = 0 and so x = 2 or x = 6
What is 3 minus x equals 8?
3 - x = 8x = 3 - 8x = - 5
Is 4y minus 8x equals negative 16 consistent or inconsistent?
It's not possible to tell without another equation that supposedly represents the same line; it's only when you have two or more "comparisons" that you can establish consistency or inconsistencies.
What is the ordered pair for 8x minus 5y equals -2?
X= -1/4. Y= -2/5. ( -.25, -0.4 )
What is x-squared minus 8x equals negative 15?
x=3
What is x squared minus 8x equals negative 12?
If: x^2 -8x = -12 then x^2-8x+12 = 0 and so x = 2 or x = 6
What is 5x minus (negative 3x)?
8x
What is 3 minus x equals 8?
3 - x = 8x = 3 - 8x = - 5
What does 2x2 minus 8x equals -8?
-1/2
How do you change negative 7 in the problem negative 7 plus 8x plus forty one equals ninety to a positive?
Change all signs, from -7 + 8x + 41 = 90 to +7 - 8x - 41 = -90
How do you factor 64x to the second power minus 80x plus 25?
64x2-80x+25 = (8x-5)(8x-5) when factored
What is 8x squared minus 8x minus 16 in factorization form?
(4x-8)(2x+2)
What is x squared minus 8x plus 8y plus 32 equals 0 in standard parabola form?
7
Is 4y minus 8x equals negative 16 consistent or inconsistent?
It's not possible to tell without another equation that supposedly represents the same line; it's only when you have two or more "comparisons" that you can establish consistency or inconsistencies.
Y-8x plus 9y equals?
Y-8x plus 9y equals 10y-8x.
What is the square root of 8x squared plus 16 minus 3x equals 0?
the answer of √8x+16-3x=0 is x= 0.447213595 = +/- 0.447(to 3 decimal places) if I'm not mistaken
