To find ( x ) such that ( x^3 = 512 ), you need to take the cube root of 512. The cube root of 512 is 8, since ( 8 \times 8 \times 8 = 512 ). Therefore, ( x = 8 ).
8 x 8 x 8 = 512
8 to the third power = 512 "To the third power" means the number times itself then times itself again (3 times the number). 8 X 8 = 64........ 64 X 8 = 512
-512 Because: -83 is just -8 x -8 x -8. -8 x -8 is 64. 64 x -8 makes it -512.
8^3 (8x8x8) = 512 7^3 (7x7x7) = 343 9^3 (9x9x9) = 729
512
8 x 8 x 8 = 512
83 = 8 x 8 x 8 = 512.
8 to the third power = 512 "To the third power" means the number times itself then times itself again (3 times the number). 8 X 8 = 64........ 64 X 8 = 512
-512 Because: -83 is just -8 x -8 x -8. -8 x -8 is 64. 64 x -8 makes it -512.
8^3 (8x8x8) = 512 7^3 (7x7x7) = 343 9^3 (9x9x9) = 729
512
8 to the third power is 8x8x8=512
512
2^(6) X 2^(3) = 2^(6+3) = 2^(9) = 512 NB Providing the coefficients is the same, '2' in this case, when multiplying you just add the indices/power/exponentials. Similarly For division , subtract the indices. 2^(6) divide 2^(3) = 2^(6-3) = 2^(3) = 8 For 'nesting' , multiply the indices. [2^(6)]^(3) = 2^(6x3) = 2^(18) = 262144 NB In all cases the coefficient MUST be the same. NNB Something along the lines of 2^(3) X 3^(2) does NOT work by adding/subtracting/nesting the indices. , because the coefficients are different.
1/512
It is: 8
x -512 = 0 Add 512 to both sides of the equation. x = 512