Possibly 222x4
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There are some operators missing that make this rather ambiguous. If you mean: 3x - 111 + x2 = x and wish to solve for x, then here's the answer: x2 + 2x - 111 = 0 x2 + 2x + 1 = 112 (x + 1)2 = 112 x + 1 = ± √112 x = -1 ± 4√7 If you mean: 3x - 111 = x2 + x Then solving for x gives us this: x2 - 2x + 111 = 0 x2 - 2x + 1 = 112 (x - 1)2 = 112 x - 1 = ± √112 x = 1 ± 4√7 If you mean: 3x - 111 + x2 + x And want to simplify it, that would be: x2 + 4x - 111 Not much really, as it can't be factored further.
x + y = 66 where x > y 2x - y = 177 rearrange the top equation: y = 66 - x substitute into the bottom: 2x - (66 - x) = 177 2x - (-x) - 66 = 177 2x + x - 66 = 177 2x + x = 111 3x = 111 x = 111/3 = 37 substitute back into the first equation: 37 + y = 66 y = 66 - 37 = 29
8x4
2x = x+3 2x-x = 3 x = 3
2x - 6 = x - 43 2x = x - 37 x = -37
X + (X+1) = 111; 2X + 1 = 111; 2X = 110; X = 55 and the other number is 56
There are some operators missing that make this rather ambiguous. If you mean: 3x - 111 + x2 = x and wish to solve for x, then here's the answer: x2 + 2x - 111 = 0 x2 + 2x + 1 = 112 (x + 1)2 = 112 x + 1 = ± √112 x = -1 ± 4√7 If you mean: 3x - 111 = x2 + x Then solving for x gives us this: x2 - 2x + 111 = 0 x2 - 2x + 1 = 112 (x - 1)2 = 112 x - 1 = ± √112 x = 1 ± 4√7 If you mean: 3x - 111 + x2 + x And want to simplify it, that would be: x2 + 4x - 111 Not much really, as it can't be factored further.
x + y = 66 where x > y 2x - y = 177 rearrange the top equation: y = 66 - x substitute into the bottom: 2x - (66 - x) = 177 2x - (-x) - 66 = 177 2x + x - 66 = 177 2x + x = 111 3x = 111 x = 111/3 = 37 substitute back into the first equation: 37 + y = 66 y = 66 - 37 = 29
111 x 111 x 111 x 111 x 111 x 111 = 1870414552161
2x+x is 3x
(2x + 1) + (x*x - 2x + 1) = x^2 + 2x - 2x + 1 + 1 = x^2 + 2
2X * 2X * 2X = 8X^3 2X^3 is saying 2*( X * X * X) = 2X^3
2x + 3 = x 2x + 3 - 3 = x - 3 2x = x - 3 2x - x = x - 3 - x x = -3
tan x + (tan x)(sec 2x) = tan 2x work dependently on the left sidetan x + (tan x)(sec 2x); factor out tan x= tan x(1 + sec 2x); sec 2x = 1/cos 2x= tan x(1 + 1/cos 2x); LCD = cos 2x= tan x[cos 2x + 1)/cos 2x]; tan x = sin x/cos x and cos 2x = 1 - 2 sin2 x= (sin x/cos x)[(1 - 2sin2 x + 1)/cos 2x]= (sin x/cos x)[2(1 - sin2 x)/cos 2x]; 1 - sin2 x = cos2 x= (sin x/cos x)[2cos2 x)/cos 2x]; simplify cos x= (2sin x cos x)/cos 2x; 2 sinx cos x = sin 2x= sin 2x/cos 2x= tan 2x
8x4
4
2x - x = x