(2x)ysquared
9! ~
(3x - y)(x + y)(3x - y)(x + y)
y2-x2 = (y+x)(y-x)
No real solutions. But if you want to find the imaginaries: x=.5(25-i(337)^.5) y=.5(25-i(337)^.5) x^.5= the square root of x
(2x)ysquared
9! ~
(3x - y)(x + y)(3x - y)(x + y)
y2-x2 = (y+x)(y-x)
No real solutions. But if you want to find the imaginaries: x=.5(25-i(337)^.5) y=.5(25-i(337)^.5) x^.5= the square root of x
3xy = 3 times 5 x 2 = 30 4y cubed = 4 times 2 x 2 x 2 =32 Total value 62
The quadratic is "sideways" which has the form: x = ay2 + by + c,or the vertex form: x = a(y - k)2 + h where (h, k) is the vertex.y2- 6x + 4y + 16 = 0y2+ 4y + 16 = 6xy2+ 4y + 4 - 4 + 16 = 6x(y + 2)2 + 12 = 6x(1/6)(y + 2)2+ 2 = x(1/6)[y -(-2)]2+ 2 = xThus, the vertex is (2, -2).
Let L = lengthLet Y = widthThe area, A, isA = LxYbut L = Y+4 soA = (Y+4) times Y = Ysquared + 4YA = Y^2 + 4Y
76 plus 54 plus 92 plus 88 plus 76 plus 88 plus 75 plus 93 plus 92 plus 68 plus 88 plus 76 plus 76 plus 88 plus 80 plus 70 plus 88plus 72 equal 1,440
The answer is 672.
27x3+6=87.
132