This is not factor-able.
(y - 7)(y - 2)
b^(2) + 8x + 7 Does NOT factor . Reason; you have two unknowns, viz. 'b' & 'x'. However, if you means b^(2) + 8b + 7 . Herewe have one unknown viz. 'b'. This factors to ( b + 7)(b + 1)
Centre = (4, -3) Radius2 = (4 + 2)2 + (-3 + 7)2 = 36 + 16 = 52 Equation = (x - 4)2 + (y + 3)2 = 52 or x2 - 8x + y2 + 6x = 27
7y+ 8x + 4= 20 + 8x- 8x - 8x7y + 4 = 20- 4 - 47y=16/7 /7y= 2.28the /7 means divide by 7 :)
8x + 7
(y - 7)(y - 2)
There is a formula for the "difference of squares." In this case, the answer is (8x + 7)(8x - 7)
b^(2) + 8x + 7 Does NOT factor . Reason; you have two unknowns, viz. 'b' & 'x'. However, if you means b^(2) + 8b + 7 . Herewe have one unknown viz. 'b'. This factors to ( b + 7)(b + 1)
It is 7+8x simplified
Centre = (4, -3) Radius2 = (4 + 2)2 + (-3 + 7)2 = 36 + 16 = 52 Equation = (x - 4)2 + (y + 3)2 = 52 or x2 - 8x + y2 + 6x = 27
7y+ 8x + 4= 20 + 8x- 8x - 8x7y + 4 = 20- 4 - 47y=16/7 /7y= 2.28the /7 means divide by 7 :)
Some signs would have helped answerers but for what its worth 7 & 8 are factors of 56 which differ by 1 so how about: (y - 7x)(y + 8x) which are the factors of y2 + xy - 56x2 or (y + 7x)(y - 8x) which are the factors of y2 - xy - 56x2.
8x-7+4 = 8x-3 simplified
y2 -y -42 = (y+6)(y-7) when factored
8x-7 plus 2x equals 6 plus 5x plus 2?
7+8x-5 = 8x+7-5x Subtract 7 from both sides: 8x-5 = 8x-5x Subtract 8x from both sides: -5 = -5x Divide both sides by -5: x = 1 So the equation implies x = 1
8x + 7