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The expression "y - 2x^3" represents a mathematical expression where "y" is a variable and "2x^3" is a term involving another variable "x." It indicates that you subtract twice the cube of "x" from "y." Without additional context or values for "y" and "x," this expression cannot be further simplified or evaluated.

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2w ago

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What is the value of 2x3 plus 15y if x equals -7 and y equals 2?

If x = -7, then x3 = -343 so that 2x3 = -686 y = 2 then 15 y = 30 So 2x3 + 15y = -686 + 30 = -656


What is the value of 2x3 plus 15yif x equals -7 and y equals 2?

x = -7, y = 2 ⇒ 2x3 + 15y = 2 x (-7)3 + 15 x 2 = 2 x (-343) + 15 x 2 = -656


2x-y plus z equals 4?

6


If X equals -1 and y equals 2 what does 2x3-3xy equal?

x = -1 y = 2 2x3 - 3xy = 2 (-1)3 - 3(-1)(2) = 2 (-1) - (-6) = -2 + 6 = 4 Suggestion: Please be careful around problems like this until you have some more experience.


How do you factor this Y equals x³ plus 3x² - 10x-24 and Y equals -x³ -6x²-3x plus 10?

It can be simplified in the form of: 2x3+9x2-7x-34 = 0


What is the answer to x plus y to 3rd power plus x minus y to 3rd power?

(x + y)3 + (x - y)3 = (x3 + 3x2y + 3xy2 + y3) + (x3 - 3x2y + 3xy2 - y3) = 2x3 + 6xy2 = 2x*(x2 + 3y2)


How do you write a expression in math?

The following are examples of expressions:2x3 + 72 × y + 52 + 6 × (4 - 2)z + 3 × (8 - z)


What is the tangent equation for 2x3-3x2-8x plus 9 when x equals 2?

The tangent to 2x3 - 3x2 - 8x + 9 at x = 2 is y = 4x - 11 The tangent to y = 2x3 - 3x2 - 8x + 9 at x = 2 has the same gradient as the curve at that point; to find the gradient, differentiate: dy/dx = 6x2 - 6x - 8 which at x = 2 is: gradient = 6 x 22 - 6 x 2 - 8 = 4 At x = 2, y = 2 x 23 - 3 x 22 - 8 x 2 + 9 = -3 The equation of a line through point (xo, yo) with gradient m is: y - yo = m(x - xo) Thus the equation of the tangent to the line at x = 2 is: y - -3 = 4(x - 2) ⇒ y = 4x - 11


How can you find 2x3?

2X3 2 + 2 + 2 = 6 3 + 3 = 6 ^ thats how ^


What is 2x3 plus 11x equals 6x?

your equation is this... 2x3 + 11x = 6x 2x3 + 5x = 0 x(2x2 + 5) = 0 x = 0 and (5/2)i and -(5/2)i


2x3 plus 3x5- 3x2 equals?

(2x3)+(3x5)-(3x2)= 2x3=6 3x5=15 3x2=6 So..... 6x25-6= 6x25=150 150+6=156


What is the f dashed x or deriative of 1 over 2xcubed plus 5?

f'(x) = 1/(2x3 + 5) rewrite f'(x) = (2X3 + 5) -1 use the chain rule d/dx (2x3 + 5) - 1 -1 * (2x3 + 5)-2 * 6x2 - 6x2(2x3 + 5) -2 ==================I would leave like this rather than rewriting this