If: 4/3y = 1 Then: y = 4/3
x = 3 y = 4 2x + y - 1 = (6) + (4) - 1 = 9
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1*1*1*1*1+1=4 divided by4
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Let N= inverse of Y Given 1/Y=4 ---> Y=1/4 inverse of 1/4 ---> 1/(1/4)=4 N=inverse of Y=4
x=4+y 4x+y=1 = 4(4+y)+y=1 16+4y+y=1 16+5y=1 5y=-15 y=-3 x=4+y = x=4+(-3) x=1
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Evaluate x/y when x = 4 and y = 4. x/y = 4/4 = 1/1 = 1
If: 4/3y = 1 Then: y = 4/3
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The slope of y = − 3 x 4 y=−3x+4 is -3. The negative reciprocal of -3 is 1 / 3 1/3. Therefore, a line perpendicular to y = − 3 x 4 y=−3x+4 and passing through (3, 4) would have a slope of 1 / 3 1/3 and can be expressed in the form y = m x b y=mx+b where m = 1 / 3 m=1/3 and ( 3 , 4 ) (3,4) satisfies the equation. To find the equation, substitute m = 1 / 3 m=1/3 and the point ( 3 , 4 ) (3,4) into the point-slope form: y − y 1 = m ( x − x 1 ) y−y 1 =m(x−x 1 ), y − 4 = ( 1 / 3 ) ( x − 3 ) y−4=(1/3)(x−3), y − 4 = ( 1 / 3 ) x − 1 y−4=(1/3)x−1, y = ( 1 / 3 ) x 3 y=(1/3)x+3. Therefore, the line perpendicular to y = − 3 x 4 y=−3x+4 and passing through (3, 4) is y = ( 1 / 3 ) x 3 y=(1/3)x+3
4(y+1)
x = 3 y = 4 2x + y - 1 = (6) + (4) - 1 = 9
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x=x-4/y 0=-4/y 0=-4 This equation is not well put together. I may have interpreted it wrong. This may be your equation and you didn't state that x-4 is a quantity x=(x-4)/y x-4=xy y=1-4/x y=-4x-1 + 1 This is slope intercept form. Your slope is -4/1 and your y-intercept is +1