y=8, 3y is 24.
If you mean 3y+24 = y-12 then the value of y works out as -18
how do you use the substitution method for this problem 2x-3y=-2 4x+y=24
For y - 2y - 3y equals 0, y equals 0.
The system is simultaneous linear equations
y=8, 3y is 24.
If you mean 3y+24 = y-12 then the value of y works out as -18
OK, so-3y + 15 - y = 39-3y + 15 - 15 - y = 39 - 15-3y -y = 24-4y = 24-y = 6y= -6.Hope this helps!
3y - 4x = 24 The first step is to write it in the standard form (y=mx + c) 3y = 4x + 24 y = (4x + 24)/3 y = 4x/3 + 8 The y-intercept is 8 and the slope/gradient is 4/3
how do you use the substitution method for this problem 2x-3y=-2 4x+y=24
For y - 2y - 3y equals 0, y equals 0.
Add 3y to each side: 12y = 24 Divide each side by 12: y = 2.
The system is simultaneous linear equations
y = -4.8, x = -1.6-4.8/-1.6 = 3y = 3xWhen y = -24-24 = 3x(divide both sides by 3)-8 = xSo x = -8
y = -2x - 8
x-intercept:2x = 24x = 12y-intercept:-3y = 24y = -8
y = 3.6 (18/5)