4x - 3y = -6Add 3y to each side:4x = -6 + 3yAdd 6 to each side:4x + 6 = 3yDivide each side by 3:(4/3)x + 2 = yThe graph is a straight line with a slope of (4/3) and a y-intercept of 2 .
5x+3y
4x+3y = 6 3y = -4x+6 y = -4/3x+2 in slope intercept form
x = 5 y = 2 4x - 3y = ? 4(5) - 3(2) = ? 20 - 6 = 14
To find the extreme value of the parabola y = x2 - 4x + 3 ...(1) Take the derivative of the equation.y = x2 - 4x + 3y' = 2x - 4(2) Set the derivative = 0 and solve for x.y' = 2x - 40 = 2x - 42x = 4x = 4/2x = 2(3) Plug this x value back into the original equation to find the associated y coordinate.x = 2y = x2 - 4x + 3y = (2)2 - 4(2) + 3y = 4 - 8 + 3y = -1So the vertex is at (2, -1).
4x - 3y = 12-3y = -4x + 12y = (4/3)x - 4^plug this transformed version of the equation into your graphing calculator or do it out by hand.
Normally, this is a difficult form of the equation to deal with. To change it into a more familiar form, we can do this: 4x + 3y = 0 3y = -4x y = (-4/3)x
4x - 3y = -6Add 3y to each side:4x = -6 + 3yAdd 6 to each side:4x + 6 = 3yDivide each side by 3:(4/3)x + 2 = yThe graph is a straight line with a slope of (4/3) and a y-intercept of 2 .
how do you use the substitution method for this problem 2x-3y=-2 4x+y=24
3y = 4x + 9 -4x + 3y = 9 is the standard form
-4x + 3y = 9
3y=4x+9.....-4xAnswer: 4x-3y=9
5x -6y=-30 5x-6y=30 (2x+3y) (2x-3y)=30 4x+6y=30 4x=30 x=30/4
(6, 0) and (0, 8)
2X - 3Y = -2 4X + Y = 24 -2(2X - 3Y = - 2) 4X + Y = 24 - 4X + 6Y = 4 4X + Y = 24 ------------------+ 7Y = 28 Y = 4 ------- insert back into one of the equations ( 4X + Y = 24 will do ) 4X +(4) = 24 4X = 20 X =5 -------- check 2(5) - 3(4) = -2 10 - 12 = -2 -2 = -2 checks I can see by inspection that the other equation checks also
4x+3y = 12 3y = -4x+12 y = -4/3x+4
4x + 3y=9 x=0 y=3