3y - 4x = 24
The first step is to write it in the standard form (y=mx + c)
3y = 4x + 24
y = (4x + 24)/3
y = 4x/3 + 8
The y-intercept is 8 and the slope/gradient is 4/3
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4x - 3y = -6Add 3y to each side:4x = -6 + 3yAdd 6 to each side:4x + 6 = 3yDivide each side by 3:(4/3)x + 2 = yThe graph is a straight line with a slope of (4/3) and a y-intercept of 2 .
5x+3y
4x+3y = 6 3y = -4x+6 y = -4/3x+2 in slope intercept form
x = 5 y = 2 4x - 3y = ? 4(5) - 3(2) = ? 20 - 6 = 14
To find the extreme value of the parabola y = x2 - 4x + 3 ...(1) Take the derivative of the equation.y = x2 - 4x + 3y' = 2x - 4(2) Set the derivative = 0 and solve for x.y' = 2x - 40 = 2x - 42x = 4x = 4/2x = 2(3) Plug this x value back into the original equation to find the associated y coordinate.x = 2y = x2 - 4x + 3y = (2)2 - 4(2) + 3y = 4 - 8 + 3y = -1So the vertex is at (2, -1).