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Use addition or substitution to find the value of y for this set of equations 4x plus 13y equals 40 4x plus 3y equals -40?
a) 4x+13y=40 b) 4x+3y=-40c) multiply b per(-1)=-4x-3y-40d) sum a and c: 4x+13y-4x-3y=40-(-40)=>10y=80 => y=8to find x replace y per its value in a or b and get x=-16
Use addition or substitution to find the value of x for this set of equations 4x plus 13y equals 40 4x plus 3y equals -40?
Try elimination.4X + 13Y = 40- 1(4X + 3Y = - 40)4X + 13Y = 40- 4X - 3Y = 40-----------------------add10Y = 80Y = 8-------------find X ( top equation )4X + 13(8) = 404X + 104 = 404X = - 64X = - 16----------------------check in both equations for consistency4(- 16) + 13(8) = 40- 64 + 104 = 4040 = 40-------------top checks4(- 16) + 3(8) = - 40- 64 + 24 = - 40- 40 = - 40-------------------both check and are consistentSo, X is,- 16 ( while Y is 8 )
What is 4x plus 3y equals 12 in slope intercept form?
4x+3y = 12 3y = -4x+12 y = -4/3x+4
Solve 4x plus 3y equals 8x plus y for y?
4x + 3y = 8x + y so 3y - y = 8x - 4x ie 2y = 4x so y = 2x
What is the solution of the system of 4x 3y-1 and x-3y-34?
If you mean: 4x+3y = -1 and x-3y = -34 then x = -7 and y = 9
