Any job of the "engineering" type will require you to do some advanced math; that would involve manipulating polynomials.
No.
Yes.
You just multiply the term to the polynomials and you combine lije terms
It might help if the question was completed!
well, we need to analyze, of course
No.
Yes.
what is the prosses to multiply polynomials
no
You just multiply the term to the polynomials and you combine lije terms
It might help if the question was completed!
It's the difference between multiplication and division. Multiplying binomials is combining them. Factoring polynomials is breaking them apart.
I do not know the answer. The choices are: AssociativeTransitiveCommutativeSymmetryDistributive
well, we need to analyze, of course
Multiplying polynomials involves distributing each term of one polynomial to every term of another, combining like terms to simplify the result. In contrast, factoring polynomials is the process of expressing a polynomial as a product of simpler polynomials or monomials. While multiplication expands expressions, factoring seeks to reverse that process by finding the original components. Both operations are fundamental in algebra and are often interconnected; for instance, factoring can be used to simplify the process of multiplication by breaking down complex polynomials.
The property is called commutativity.
It means you multiply the binomial by itself. Multiplying polynomials requires multiplying every term of the first with every term of the second. For example, (a+b)2 = a2 + ab + ba + b2 = a2 + 2ab + b2.It means you multiply the binomial by itself. Multiplying polynomials requires multiplying every term of the first with every term of the second. For example, (a+b)2 = a2 + ab + ba + b2 = a2 + 2ab + b2.It means you multiply the binomial by itself. Multiplying polynomials requires multiplying every term of the first with every term of the second. For example, (a+b)2 = a2 + ab + ba + b2 = a2 + 2ab + b2.It means you multiply the binomial by itself. Multiplying polynomials requires multiplying every term of the first with every term of the second. For example, (a+b)2 = a2 + ab + ba + b2 = a2 + 2ab + b2.